PHP - 在每个多维数组中添加一个新元素答案

【问题标题】：PHP - Add a new element into each multidimensional arrayPHP - 在每个多维数组中添加一个新元素
【发布时间】：2021-12-30 21:15:16
【问题描述】：

我有一个如下所示的数组：

Array
(
    [0] => stdClass Object
        (
            [quiz_id] => 1033
            [quiz_venue] => 6
            [quiz_host] => 46
            [quiz_golden_question] => 100
            [quiz_golden_question_outcome] => 0
            [quiz_running] => 1
            [quiz_status] => 100
            [quiz_trainee] => 0
        )

    [1] => stdClass Object
        (
            [quiz_id] => 985
            [quiz_venue] => 57
            [quiz_host] => 21
            [quiz_golden_question] => 0
            [quiz_golden_question_outcome] => 0
            [quiz_running] => 1
            [quiz_status] => 310
            [quiz_trainee] => 0
        )

我想遍历每个数组，并插入一个新值（quiz_venue_name），这就是我所拥有的；

$quizzes = $wpdb->get_results( $prepared );

        foreach ($quizzes as $quiz => $item) { 
            $venuetitle = get_the_title($item->quiz_venue);
            $quizzes['quiz_venue_name'] = $venuetitle;
        }

        return $quizzes;

但是，它所做的只是将新值作为新数组添加到多维数组的最后 - 而不是将它们添加到每个数组中！

我觉得我做错了什么，所以非常感谢任何帮助！

我需要的最终结果是；

Array
(
    [0] => stdClass Object
        (
            [quiz_id] => 1033
            [quiz_venue] => 6
            [quiz_host] => 46
            [quiz_golden_question] => 100
            [quiz_golden_question_outcome] => 0
            [quiz_running] => 1
            [quiz_status] => 100
            [quiz_trainee] => 0
[quiz_venue_name] => NEW VALUE
        )

    [1] => stdClass Object
        (
            [quiz_id] => 985
            [quiz_venue] => 57
            [quiz_host] => 21
            [quiz_golden_question] => 0
            [quiz_golden_question_outcome] => 0
            [quiz_running] => 1
            [quiz_status] => 310
            [quiz_trainee] => 0
[quiz_venue_name] => NEW VALUE
        )

【问题讨论】：

标签： php arrays

【解决方案1】：

您的$quizzes 变量是一个对象数组（stdClass 的实例），因此您应该使用它的属性在每次迭代中设置值（$item->quiz_venue_name 而不是$quizzes['quiz_venue_name']）：

...
foreach ($quizzes as $quiz => $item) { 
    $venuetitle = get_the_title($item->quiz_venue);
    $item->quiz_venue_name = $venuetitle;
}
...

事实上，$quizzes['quiz_venue_name']=... 代码将在$quizzes 数组的根中为索引quiz_venue_name 设置一个值。

【讨论】：