将具有嵌套数组的数组转换为没有嵌套数组的新数组（JavaScript）[重复]

Question

我的数组 "arrs" 带有嵌套数组，如下所示：

let arrs = ["Apple", ["Peach", "Grape"], [["Pear", "Kiwi"], ["Lemon"]]];

现在，我想将数组 "arrs" 转换为没有嵌套数组的新数组 "newArr"，如下所示：

let newArr = [ "Apple", "Peach", "Grape", "Pear", "Kiwi", "Lemon" ];

我创建了将 "arrs" 转换为 "newArr" 而没有嵌套数组的代码：

let newArr = [arrs[0], arrs[1][0], arrs[1][1], arrs[2][0][0], arrs[2][0][1], arrs[2][1][0]];

console.log(newArr); // [ "Apple", "Peach", "Grape", "Pear", "Kiwi", "Lemon" ]

这是完整的可运行代码：

let arrs = ["Apple", ["Peach", "Grape"], [["Pear", "Kiwi"], ["Lemon"]]];

let newArr = [arrs[0], arrs[1][0], arrs[1][1], arrs[2][0][0], arrs[2][0][1], arrs[2][1][0]];

console.log(newArr); // [ "Apple", "Peach", "Grape", "Pear", "Kiwi", "Lemon" ]

但是，我想让这段代码更简单、更酷或更聪明。有没有办法做到这一点？

let newArr = [arrs[0], arrs[1][0], arrs[1][1], arrs[2][0][0], arrs[2][0][1], arrs[2][1][0]];

console.log(newArr); // [ "Apple", "Peach", "Grape", "Pear", "Kiwi", "Lemon" ]

Answer 1

您可以将 "flat()" 与 "2" 一起使用：

let arrs = ["Apple", ["Peach", "Grape"], [["Pear", "Kiwi"], ["Lemon"]]];

let newArr = arrs.flat(2);

console.log(newArr); // [ "Apple", "Peach", "Grape", "Pear", "Kiwi", "Lemon" ]

此外，您可以将 "flat()" 与 "Infinity" 一起用于任何深度的嵌套数组。

let arrs = ["Apple", ["Peach", "Grape"], [["Pear", "Kiwi"], ["Lemon"]]];

let newArr = arrs.flat(Infinity);

console.log(newArr); // [ "Apple", "Peach", "Grape", "Pear", "Kiwi", "Lemon" ]