使用滑动窗口将链接分成块

Question

所以，我试图将列表分成 4 块，但需要注意的是。需要注意的是，我希望列表获取前一个块的最后 2 个元素并将其与接下来的 2 个元素连接起来以产生以下输出：

例如：

Input: text=['one','two','three','four','five','six','seven','eight']
Output: ['one two three four','three four five six', 'five six seven eight']

现在，我有这个：

from itertools import islice

text=['one','two','three','four','five','six','seven','eight']

def window(seq, n=2):
    "Returns a sliding window (of width n) over data from the iterable"
    "   s -> (s0,s1,...s[n-1]), (s1,s2,...,sn), ...                   "
    it = iter(seq)
    result = tuple(islice(it, n))
    if len(result) == n:
        yield result
    for elem in it:
        result = result[1:] + (elem,)
        yield result

processed = [' '.join(i) for i in window(text,4)]
print(processed)
Output:
['one two three four', 'two three four five', 'three four five six', 'four five six seven', 'five six seven eight']

同样，我的理想输出是：

['one two three four','three four five six', 'five six seven eight']

Answer 1

这样的？

data = 'i ii iii iv v vi vii viii'.split()

print([' '.join(data[i-2:i+2]) for i in range(2, len(data), 2)])