Bash shell 数组操作

Question

我有一个小脚本，它从文本文件中读取行并将它们存储在一个数组中。

#!/bin/bash

while read line 
do
    array+=("$line")
done < $1

for ((i=0; i < ${#array[*]}; i++))
do
    echo "${array[i]}"
done

这是我运行脚本后打印的文本文件中的行：

This is line1 of file1 with 10 words.
This is line2 of file2 with 100 words.
This is line3 of file3 with 1000 words.
...

到目前为止还不错。从这里开始，我试图在行中使用单词并形成一个新的语句集。最终输出将按以下格式构造：

Capture ThisFile info-count1
filenum file1
Position of line: line1; Count of words: 10

有没有一种方法可以遍历每个数组元素（行字）并执行此操作？

基本上，从这里开始，当我在数组中有行时，我想遍历每一行，选择行中的某些单词并创建一个新的语句集。

..... 更新： .....

这就是我最终完成的方式：

#!/bin/bash

while read line
do
    getthelines=($line)
    printf '\n'
    echo "Capture ThisFile info_count"
    echo "filenum ${getthelines[4]}"
    echo "Position of line: ${getthelines[2]}; Count of words: ${getthelines[6]}"
    printf '\n'
done < $1

非常感谢。

另见：

• Split string into an array in Bash
• Redirect output to a bash array
• How to iterate over associative arrays in Bash
• Iterate over bash arrays, substitute array name dynamically, is this possible?

Answer 1

没办法。我昨天写了这段代码来迭代一个数组。

line="This is line1 of file1 with 10 words."
words=($line)
for word in ${words[@]};
do 
    echo "Word: $word"
done

输出：

Word: This
Word: is
Word: line1
Word: of
Word: file1
Word: with
Word: 10
Word: words.