从销售数据创建汇总表的功能

Question

我正在寻找创建汇总表的函数，我可以在其中将表作为输入参数传递并创建如下所示的汇总，我正在尝试使用 dcast 创建，但无法使其对变量进行动态化。

示例数据框

target <- c("DT 0", "DT 1", "DT 2", "DT 3", "DT 4", "DT 5", "DT 6", "DT 7", "DT 8")
basic <- c(19,50,79,80,72,30,13,45,52)
beginner <- c(22,82,50,15,51,54,40,17,31)
medium <- c(18,66,29,32,40,34,57,60,84)
projected <- c(38,63,17,64,81,41,14,63,79)
Planned <- c(53,12,73,34,16,77,12,60,88)
df <- data.frame(target,basic,beginner,medium,projected,Planned)
df <- as.data.frame(t(df))

所需的输出应如下所示

Answer 1

你可以使用：

library(dplyr)
library(tidyr)

df %>%
  select(target, basic, Planned) %>%
  pivot_wider(names_from = target, values_from = c(basic, Planned), 
              names_glue = '{target}_{.value}') %>%
  select(order(stringr::str_extract(names(.), 'DT \\d+')))

如果您使用的是数据的转置版本，请使用以下代码。

df %>%
  rownames_to_column('val') %>%
  filter(val %in% c('target', 'basic', 'Planned')) %>%
  t %>%
  as.data.frame() %>%
  setNames(.[1, ]) %>%
  slice(-1) %>%
  pivot_wider(names_from = target, values_from = c(basic, Planned), 
              names_glue = '{target}_{.value}') %>%
  select(order(stringr::str_extract(names(.), 'DT \\d+')))

R 数据框不能有多个标题，如果您希望输出看起来与显示的完全一样，您可以查看 knitr::kable 或 gt::gt 之类的函数以及其他显示漂亮表格的函数。

Answer 2

这是我能想到的最好的方法，但是到目前为止我还不能从第二个标题中删除 DT_ 部分，因为名称应该是唯一的并且它会抛出错误。我会尽快弄明白的。

library(dplyr)
library(tidyr)
library(kableExtra)

df %>% 
  pivot_longer(- target, names_to = "summary", values_to = "Banking") %>%
  filter(summary %in% c("basic", "Planned"),
         target %in% c("DT 0", "DT 5", "DT 8")) %>%
  pivot_wider(names_from = c("target", "summary"), values_from = Banking) %>%
  mutate(`Sales Review` = "Banking") %>%
  relocate(`Sales Review`) %>%
  kbl() %>%
  kable_classic() %>%
  add_header_above(c(" "= 1, "DT 0" = 2, "DT 5" = 2, "DT 8" = 2))

这是输出。