【发布时间】:2016-12-30 04:13:20
【问题描述】:
如果我需要将人员的电子邮件 ID 及其姓名导入数据库,我必须编写代码,这些姓名将在 Excel 工作表上导入数据库,但面临的问题是它向我显示文件所在的无效文件.csv 格式,请帮助,我是这个概念的新手,如果我在某个地方出错了,请原谅我。
import.php
<form action="<?php echo $_SERVER["PHP_SELF"]; ?>" method="post" enctype="multipart/form-data">
<input type="file" name="sel_file" size="20" /><br />
<input type="submit" name="submit" value="Submit" />
</form>
<?php
include ("connection.php");
if(isset($_POST["submit"]))
{
$fname = $_FILES['sel_file']['tmp_name'];
echo'Upload file name is'.$fname.' ';
$chk_ext = explode(".",$fname);
if(strtolower(end($chk_ext)) == "csv"){
$filename = $_FILES['sel_file'] ['tmp_name'];
$handle = fopen($filename, "r");
while(($data = fgetcsv($handle, 1000, ",")) !== false)
{
$sql = "INSERT into import_email (vault_no, name, email) values ('".$_SESSION['vault_no']."', '$data[0]', '$data[1]')";
mysql_query($sql) or die(mysql_error());
}
fclose($handle);
echo "Successfully imported! ";
}else{
echo "Invalid file!";
}
}
?>
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