【发布时间】:2020-09-02 10:44:46
【问题描述】:
我一直在尝试从不同的 url 下载数据,然后将其保存到 csv 文件中。
这个想法是从以下位置提取突出显示的数据:https://www.marketwatch.com/investing/stock/MMM/financials/cash-flow
到目前为止,我构建了以下代码:
import pandas as pd
from bs4 import BeautifulSoup
import urllib.request as ur
url_is = 'https://www.marketwatch.com/investing/stock/MMM/financials/cash-flow'
read_data = ur.urlopen(url_is).read()
soup_is=BeautifulSoup(read_data, 'lxml')
row = soup_is.select_one('tr.mainRow>td.rowTitle:contains("Cash Dividends Paid - Total")')
data=[cell.text for cell in row.parent.select('td') if cell.text!='']
df=pd.DataFrame(data)
print(df.T)
我得到一个输出:
到目前为止一切顺利。
现在我的想法是从多个 URL 中提取特定的类,从网站中保留相同的标题并将其导出到 .csv。
标签和类保持不变
示例网址:
https://www.marketwatch.com/investing/stock/MMM/financials/cash-flow
https://www.marketwatch.com/investing/stock/aapl/financials/cash-flow
代码(我想尝试 2 列:2015 和 2016)
我写了以下代码,但给我带来了问题,欢迎任何帮助或建议:
import pandas as pd
from bs4 import BeautifulSoup
import urllib.request as ur
import numpy as np
import requests
links = ['https://www.marketwatch.com/investing/stock/aapl/financials/cash-flow', 'https://www.marketwatch.com/investing/stock/MMM/financials/cash-flow']
container = pd.DataFrame(columns=['Name', 'Name2'])
pos=0
for l in links:
read_data = ur.urlopen(l).read()
soup_is=BeautifulSoup(read_data, 'lxml')
row = soup_is.select_one('tr.mainRow>td.rowTitle:contains("Cash Dividends Paid - Total")')
results=[cell.text for cell in row.parent.select('td') if cell.text!='']
records = []
for result in results:
records = []
Name = result.find('span', attrs={'itemprop':'2015'}).text if result.find('span', attrs={'itemprop':'2015'}) is not None else ''
Name2 = result.find('span', attrs={'itemprop':'2016'}).text if result.find('span', attrs={'itemprop':'2016'}) is not None else ''
records.append(Name)
records.append(Name2)
container.loc[pos] = records
pos+=1
【问题讨论】:
标签: python python-3.x web-scraping beautifulsoup export-to-csv