【发布时间】:2021-03-23 05:35:39
【问题描述】:
我的数据目前在Stata中组织如下:
iso_code indicator value
ALB Share of employees in agriculture (% of total employees) 2.52084
ARG Employment in agriculture 11.153
ARG Share of employees in agriculture (% of total employees) .104509
AUS Employment in agriculture 329.66
AUS Share of employees in agriculture (% of total employees) 1.47018
AUT Employment in agriculture 159.549
AUT Employment-to-population ratio, rural areas 60.4239
AUT Labour force participation rate, rural areas 61.9622
AUT Share of employees in agriculture (% of total employees) .838354
AZE Employment in agriculture 1769.3
我希望每个国家都在一行中,然后将变量名称及其值作为单独的列。
iso_code Employment in agriculture Share of employees in agriculture (% of total employees)
AUT 159.549 .838354
我尝试了以下代码,但一直收到此错误:“indicator.1720000058412552 invalid variable name”
reshape wide indicator value, i(iso_code) j(value)
【问题讨论】:
标签: stata reshape data-manipulation