这是一个相当简单的“宽”到“长”问题。以下是三种方法:
使用“reshape2”
library(reshape2)
melt(df, id.vars = c("ID", "T"), variable.name = "Channel", value.name = "P")
# ID T Channel P
# 1 1 24.3 P.1 10.2
# 2 2 23.4 P.1 10.4
# 3 3 22.1 P.1 10.5
# 4 4 19.9 P.1 10.2
# 5 1 24.3 P.2 5.5
# 6 2 23.4 P.2 5.7
# 7 3 22.1 P.2 5.9
# 8 4 19.9 P.2 5.2
# 9 1 24.3 P.3 2.1
# 10 2 23.4 P.3 2.8
# 11 3 22.1 P.3 3.1
# 12 4 19.9 P.3 2.4
带有基数 R 的 reshape
reshape(df, direction = "long",
idvar = c("ID", "T"),
timevar = "Channel",
varying = 3:ncol(df))
# ID T Channel P
# 1.24.3.1 1 24.3 1 10.2
# 2.23.4.1 2 23.4 1 10.4
# 3.22.1.1 3 22.1 1 10.5
# 4.19.9.1 4 19.9 1 10.2
# 1.24.3.2 1 24.3 2 5.5
# 2.23.4.2 2 23.4 2 5.7
# 3.22.1.2 3 22.1 2 5.9
# 4.19.9.2 4 19.9 2 5.2
# 1.24.3.3 1 24.3 3 2.1
# 2.23.4.3 2 23.4 3 2.8
# 3.22.1.3 3 22.1 3 3.1
# 4.19.9.3 4 19.9 3 2.4
使用“tidyr”+“dplyr”
library(dplyr)
library(tidyr)
df %>%
gather(Channel, P, P.1:P.3) %>%
mutate(Channel = gsub("P.", "", Channel))
# ID T Channel P
# 1 1 24.3 1 10.2
# 2 2 23.4 1 10.4
# 3 3 22.1 1 10.5
# 4 4 19.9 1 10.2
# 5 1 24.3 2 5.5
# 6 2 23.4 2 5.7
# 7 3 22.1 2 5.9
# 8 4 19.9 2 5.2
# 9 1 24.3 3 2.1
# 10 2 23.4 3 2.8
# 11 3 22.1 3 3.1
# 12 4 19.9 3 2.4