【问题标题】:Playing sound byte[] in C#在 C# 中播放声音字节 []
【发布时间】:2011-09-04 08:47:53
【问题描述】:

我意识到您可以使用SoundPlayer 在 C# 中播放声音;但是,我希望能够使用此方法从字节数组中表示的声音中使用操作系统默认的声音播放器播放声音。这可能吗?

【问题讨论】:

  • 你的 byte[] 的来源是什么?是 wav 还是什么?

标签: c# .net audio file-io


【解决方案1】:

SoundPlayer 构造函数接受要播放的 Stream。您可以通过创建 MemoryStream 从 byte[] 获取 Stream。

【讨论】:

    【解决方案2】:

    使用应用程序打开任何文件,例如媒体播放器,需要一个文件。

    因此,您需要将字节数组以某种格式保存到文件中,例如WAV,然后打开它:

    byte[] bytes = ...
    string name = Path.ChangeExtension(Path.GetRandomFileName(), ".wav");
    string path = Path.Combine(Path.GetTempPath(), name);
    File.WriteAllBytes(path, bytes);
    Process.Start(path);
    

    此代码将打开用户默认媒体播放器,就像您在 Windows 资源管理器中单击它一样。

    【讨论】:

    • 好吧,我也很怀疑!谢谢。
    • @user624071:很高兴它有帮助:)
    【解决方案3】:

    abatishchev 有一个很好的答案,但您不需要将字节保存到文件然后播放文件。您可以将这些字节写入 MemoryStream,然后像此方法一样播放 MemoryStream:

    using System;
    using System.Collections.Generic;
    using System.IO;
    using System.Linq;
    using System.Windows.Forms;
    
    public static void PlayBeep(UInt16 frequency, int msDuration, UInt16 volume = 16383)
    {
        var mStrm = new MemoryStream();
        BinaryWriter writer = new BinaryWriter(mStrm);
    
        const double TAU = 2 * Math.PI;
        int formatChunkSize = 16;
        int headerSize = 8;
        short formatType = 1;
        short tracks = 1;
        int samplesPerSecond = 44100;
        short bitsPerSample = 16;
        short frameSize = (short)(tracks * ((bitsPerSample + 7) / 8));
        int bytesPerSecond = samplesPerSecond * frameSize;
        int waveSize = 4;
        int samples = (int)((decimal)samplesPerSecond * msDuration / 1000);
        int dataChunkSize = samples * frameSize;
        int fileSize = waveSize + headerSize + formatChunkSize + headerSize + dataChunkSize;
        // var encoding = new System.Text.UTF8Encoding();
        writer.Write(0x46464952); // = encoding.GetBytes("RIFF")
        writer.Write(fileSize);
        writer.Write(0x45564157); // = encoding.GetBytes("WAVE")
        writer.Write(0x20746D66); // = encoding.GetBytes("fmt ")
        writer.Write(formatChunkSize);
        writer.Write(formatType);
        writer.Write(tracks);
        writer.Write(samplesPerSecond);
        writer.Write(bytesPerSecond);
        writer.Write(frameSize);
        writer.Write(bitsPerSample);
        writer.Write(0x61746164); // = encoding.GetBytes("data")
        writer.Write(dataChunkSize);
        {
            double theta = frequency * TAU / (double)samplesPerSecond;
            // 'volume' is UInt16 with range 0 thru Uint16.MaxValue ( = 65 535)
            // we need 'amp' to have the range of 0 thru Int16.MaxValue ( = 32 767)
            double amp = volume >> 2; // so we simply set amp = volume / 2
            for (int step = 0; step < samples; step++)
            {
                short s = (short)(amp * Math.Sin(theta * (double)step));
                writer.Write(s);
            }
        }
    
        mStrm.Seek(0, SeekOrigin.Begin);
        new System.Media.SoundPlayer(mStrm).Play();
        writer.Close();
        mStrm.Close();
    } // public static void PlayBeep(UInt16 frequency, int msDuration, UInt16 volume = 16383)
    

    对于您的问题,您不需要此方法中用于创建 WAV 格式字节流的大部分代码,但您可以在方法末尾使用该技巧来避免将字节保存到文件中。

    【讨论】:

    【解决方案4】:

    How to play from an array试试

    PlayerEx pl = new PlayerEx();
    
    private static void PlayArray(PlayerEx pl)
    {
        double fs = 8000; // sample freq
        double freq = 1000; // desired tone
        short[] mySound = new short[4000];
        for (int i = 0; i < 4000; i++)
        {
            double t = (double)i / fs; // current time
            mySound[i] = (short)(Math.Cos(t * freq) * (short.MaxValue));
        }
        IntPtr format = AudioCompressionManager.GetPcmFormat(1, 16, (int)fs);
        pl.OpenPlayer(format);
        byte[] mySoundByte = new byte[mySound.Length * 2];
        Buffer.BlockCopy(mySound, 0, mySoundByte, 0, mySoundByte.Length);
        pl.AddData(mySoundByte);
        pl.StartPlay();
    }
    

    【讨论】:

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