Y轴从一列x从不同列到不同的子图[重复]答案

【问题标题】：Y axis from one column x from different column into different subplots [duplicate]Y轴从一列x从不同列到不同的子图[重复]
【发布时间】：2020-12-03 10:08:38
【问题描述】：

您好，我有一个数据框：

data1 = {"x": [10,20,30,40,50], 
         "y": [0.01,0.02,0.03,0.04,0.05],
         "z": [0.11,0.12,0.13,0.14,0.15],
         "q": [0.21,0.22,0.23,0.24,0.25],}
df1 = pd.DataFrame (data1, columns = ['x','y','z','q'])

我想创建一个 x 与 y、z 和 q 的图作为图上的子图。

我已经这样做了，但是他们在同一个情节上

import matplotlib.pyplot as plt

plt.plot(df1['y'], df1['x'])
plt.plot(df1['z'], df1['x'])
plt.plot(df1['q'], df1['x'])

另外有没有办法为 eahc 行添加标签？

【问题讨论】：

标签： python python-3.x pandas matplotlib plot

【解决方案1】：

要为每一行添加图例，您可以为每一行分配一个标签，然后调用plt.legend() 来绘制图例。

import pandas as pd
import matplotlib.pyplot as plt

data1 = {"x": [10,20,30,40,50], 
         "y": [0.01,0.02,0.03,0.04,0.05],
         "z": [0.11,0.12,0.13,0.14,0.15],
         "q": [0.21,0.22,0.23,0.24,0.25],}
df1 = pd.DataFrame (data1, columns = ['x','y','z','q'])

plt.plot(df1['y'], df1['x'], label='y')
plt.plot(df1['z'], df1['x'], label='z')
plt.plot(df1['q'], df1['x'], label='q')

plt.legend()

plt.show()

要将它们绘制在不同的子图上，您可以通过在 plt.subplots() 中定义 nrows 和 ncols 参数来创建 mxn 子图。然后在每个坐标区对象上绘制数据。

import pandas as pd
import matplotlib.pyplot as plt

data1 = {"x": [10,20,30,40,50], 
         "y": [0.01,0.02,0.03,0.04,0.05],
         "z": [0.11,0.12,0.13,0.14,0.15],
         "q": [0.21,0.22,0.23,0.24,0.25],}
df1 = pd.DataFrame (data1, columns = ['x','y','z','q'])

figure, axs = plt.subplots(nrows=1, ncols=3, figsize=(8, 4))

axs[0].plot(df1['y'], df1['x'], label='y')
axs[1].plot(df1['z'], df1['x'], label='z')
axs[2].plot(df1['q'], df1['x'], label='q')

axs[0].set_title('x against y')
axs[1].set_title('x against z')
axs[2].set_title('x against q')

plt.show()

【讨论】：