我必须维护一个没有文档的旧项目，并且有一个包含很多表和函数以及存储过程的数据库。我想在表和存储过程之间建立一个依赖树，例如，这个过程执行这些过程并使用这些表。
有什么工具可以帮到我
如果没有，这些算法的起点是什么？我的意思是我可以从数据库中获取所有过程的源代码，然后解析它以获取所有 'exec #'、'update #'、'insert into #' 等等。在这种情况下，解决这个问题的最佳方法是什么（可能是正则表达式，或者一些特殊算法......）？
【问题讨论】：
标签： sql-server database parsing text
有像 redgate 这样的付费工具，但如果需要，您可以随时右键单击对象并选择“查看依赖项”。
【讨论】：
Higarian，您的代码对我非常有用。我对其进行了一些改进，以消除循环依赖，包括表引用，并按 ObjectPath 排序。
;with ObjectHierarchy ( Base_Object_Id , Base_Cchema_Id , Base_Object_Name , Base_Object_Type, object_id , Schema_Id , Name , Type_Desc , Level , Obj_Path)
as
( select so.object_id as Base_Object_Id
, so.schema_id as Base_Cchema_Id
, so.name as Base_Object_Name
, so.type_desc as Base_Object_Type
, so.object_id as object_id
, so.schema_id as Schema_Id
, so.name
, so.type_desc
, 0 as Level
, convert ( nvarchar ( 1000 ) , N'/' + so.name ) as Obj_Path
from sys.objects so
left join sys.sql_expression_dependencies ed on ed.referenced_id = so.object_id
left join sys.objects rso on rso.object_id = ed.referencing_id
where rso.type is null
and so.type in ( 'P', 'V', 'IF', 'FN', 'TF' )
union all
select cp.Base_Object_Id as Base_Object_Id
, cp.Base_Cchema_Id
, cp.Base_Object_Name
, cp.Base_Object_Type
, so.object_id as object_id
, so.schema_id as ID_Schema
, so.name
, so.type_desc
, Level + 1 as Level
, convert ( nvarchar ( 1000 ) , cp.Obj_Path + N'/' + so.name ) as Obj_Path
from sys.objects so
inner join sys.sql_expression_dependencies ed on ed.referenced_id = so.object_id
inner join sys.objects rso on rso.object_id = ed.referencing_id
inner join ObjectHierarchy as cp on rso.object_id = cp.object_id and rso.object_id <> so.object_id
where so.type in ( 'P', 'V', 'IF', 'FN', 'TF', 'U')
and ( rso.type is null or rso.type in ( 'P', 'V', 'IF', 'FN', 'TF', 'U' ) )
and cp.Obj_Path not like '%/' + so.name + '/%' ) -- prevent cycles n hierarcy
select Base_Object_Name
, Base_Object_Type
, REPLICATE ( ' ' , Level ) + Name as Indented_Name
, SCHEMA_NAME ( Schema_Id ) + '.' + Name as object_id
, Type_Desc as Object_Type
, Level
, Obj_Path
from ObjectHierarchy as p
order by Obj_Path
【讨论】：
有人提到了 Redgate 的付费插件。 ApexSQL 是另一家为 SQL Server 制作附加组件的公司。其中一些需要花钱，但其他一些是免费的，仍然非常有用。
ApexSQL 搜索 是免费的搜索之一。它的两个主要特点是：
安装后，只需右键单击一个对象或数据库，然后单击View dependencies（靠近底部，旁边有一个图标）。不要将它与View Dependencies（靠近顶部，旁边没有图标）混淆，它是 SQL Server 中内置的。我发现层次图布局是最有用的。
链接：
【讨论】：
这里，max(level) 应该可以解决您的问题而无需外部工具
;WITH cte ( [ID] ,IDSchema,Nome,Tipo,level, SortCol)
AS (SELECT [so].[object_id] AS ID
,so.[schema_id],so.[name],so.[type]
,0 AS [Level]
,CAST ([so].[object_id] AS VARBINARY (MAX)) AS SortCol
FROM [sys].[objects] so
LEFT JOIN sys.sql_expression_dependencies ed ON [ed].[referenced_id]=[so].[object_id]
LEFT JOIN [sys].[objects] rso ON rso.[object_id]=[ed].referencing_id
--in my database, if i insert tables on the search, it gets more tham 100 levels of recursivity, and that is bad
WHERE [rso].[type] IS NULL AND [so].[type] IN ('V','IF','FN','TF','P')
UNION ALL
SELECT [so].[object_id] AS ID
,so.[schema_id],so.[name],so.[type]
,Level + 1
,CAST (SortCol + CAST ([so].[object_id] AS BINARY (4)) AS VARBINARY (MAX))
FROM [sys].[objects] so
INNER JOIN sys.sql_expression_dependencies ed ON [ed].[referenced_id]=[so].[object_id]
INNER JOIN [sys].[objects] rso ON rso.[object_id]=[ed].referencing_id
INNER JOIN cte AS cp ON rso.[object_id] = [cp].[ID]
WHERE [so].[type] IN ('V','IF','FN','TF','P')
AND ([rso].[type] IS NULL OR [rso].[type] IN ('V','IF','FN','TF','P'))
)
--CTE
SELECT ID, IDSchema,
REPLICATE(' ',level)+nome AS Nome,'['+SCHEMA_NAME(IDSchema)+'].['+nome+']' AS Object,Tipo,Level,SortCol
FROM cte AS p
ORDER BY sortcol
【讨论】：
您可以使用如下所示的 sys.dm_sql_referenced_entities 来获取任何对象的所有依赖项
SELECT
*
FROM
sys.dm_sql_referenced_entities('dbo.myStoredProcedure', 'OBJECT')
【讨论】：