如何用spss文件中data.frames中的标签替换值？

Question

我必须读取一个 sav 文件 我使用包haven

library(haven)
dataset<- read_sav("datafile.sav")

在控制台中我可以看到标签：

        dput(head(voyages$portdep))
        structure(c(50422, 50299, 50299, 50299, NA, NA), label = "Port of departure", labels = c(Alicante = 10101, 
        Barcelona = 10102, Bilbao = 10103, Cadiz = 10104, Figuera = 10105, 
        Gibraltar = 10106, `La Coruña` = 10107, Santander = 10110, Seville = 10111, 
        `San Lucar` = 10112, Vigo = 10113, `Spain, port unspecified` = 10199, 
        Lagos = 10202, Lisbon = 10203, Oporto = 10204, `Ilho do Fayal` = 10205, 
        Setubal = 10206, `Portugal, port unspecified` = 10299, `Great Britain, port unspecified` = 10399, 
        Barmouth = 10401, Bideford = 10402, Birkenhead = 10403, Bristol = 10404, 
        Brixham = 10405, Broadstairs = 10406, Cawsand = 10407, Chepstow = 10408, 
        Chester = 10409, Colchester = 10410, Cowes = 10411, Dartmouth = 10412, 
        Deptford = 10413, Dover = 10414, Exeter = 10415, Folkstone = 10416, 
        Frodsham = 10417, Gainsborough = 10418, Greenwich = 10419, Guernsey = 10420, 
        Harwich = 10421, Hull = 10422, Ilfracombe = 10423, Ipswich = 10424, 
        `Isle of Man` = 10425, `Isle of Wight` = 10426, Jersey = 10427, 
        Kendal = 10428, `King's Lynn` = 10429, Lancaster = 10430, Lindale = 10431, 
        Liverpool = 10432, London = 10433, Lyme = 10434, Maryport = 10436, 
        `Milford Haven` = 10437, `New Shoreham` = 10438, `Newcastle upon Tyne` = 10439, 
        Newnham = 10440, `North Shields` = 10441, Norwich = 10443, Padstowe = 10444, 
        Parkgate = 10445, `Piel of Foulney` = 10446, Plymouth = 10447, 
        Poole = 10448, Portsery = 10449, Portsmouth = 10450, Poulton = 10451, 
        Preston = 10452, Ramsgate = 10453, Ravenglass = 10454, `River Thames` = 10455, 
        Rochester = 10456, Rotherhithe = 10457, Rye = 10458, Scarborough = 10459, 
        Sheerness = 10460, Shields = 10461, Shoreham = 10462, Sidmouth = 10463, 
        Southampton = 10464, Stockton = 10466, Stockwithe = 10467, Sunderland = 10468, 
        Teignmouth = 10469, Topsham = 10470, Torbay = 10471, Wales = 10472, 

在 html 表中，我只有值：

如何用spss文件中data.frames中的标签替换值？用于在html表格中显示？

使用 sjlabelled 包，我可以获得任何列的标签：

library(sjlabelled)
get_labels(voyages$portdep)

1] “阿利坎特” “巴塞罗那” “毕尔巴鄂” “加的斯”
[5] “菲格拉”“直布罗陀”“拉科鲁尼亚”“桑坦德”
[9] “塞维利亚”“圣卢卡尔”“维戈”“西班牙，未指定港口”
[13] 《拉各斯》《里斯本》《波尔图》《伊洛杜法亚尔》
[17] “塞图巴尔” “葡萄牙，未指定港口” “英国，未指定港口” “巴茅斯”
[21] “比德福德”“伯肯黑德”“布里斯托”“布里克瑟姆”
[25] “Broadstairs” “Cawsand” “Chepstow” “Chester”
[29] “科尔切斯特”“考斯”“达特茅斯”“德普特福德”
[33] “多佛”“埃克塞特”“福克斯通”“弗罗德舍姆”
[37] “盖恩斯伯勒”“格林威治”“根西岛”“哈里奇”
[41] “赫尔”“伊尔弗勒科姆”“伊普斯维奇”“马恩岛”
[45]“怀特岛”“泽西岛”“肯德尔”“金斯林恩”

我试过了：

在单列上：

  dataset2 <- dataset %>% mutate(portdep = get_labels(portdep))

错误：列 portdep 的长度必须为 36002（行数）或 一，不是847

在所有数据框上：

  dataset2 <-  dataset %>% mutate_all(funs(get_labels(.)))

第一列出现同样的错误：

列 xxx 的长度必须为 36002（行数）或 1，而不是 2

Answer 1

我认为您可以通过使用haven::as_factor 获得所需的内容。

这行得通吗？

library(haven)
library(dplyr)

dataset %>% 
  mutate_all(as_factor) %>%
  head() %>%
  View()

Answer 2

您可以尝试foreign，而不是使用haven 包。我使用了我自己的数据try.sav，包括一个变量gender：

library(haven)
df_haven<- read_sav("try.sav")
class(df_haven$gender)
#> [1] "haven_labelled"
table(df_haven$gender)
#> 
#>    1    2 
#> 1972 2417
df_haven$gender
#> <Labelled double>: Gender
#>    [1] 2 2 2 1 2 2 2 2 2 2 2 2 2 1 2 2 2 2 2 1 2 2 2 2 2 2 1 1 1 1 2 2 2 2 2 2 2
#>   [38] 2 2 2 1 2 2 1 2 2 2 2 2 2 2 2 1 2 2 2 2 1 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2
#>   [75] 2 2 1 1 2 2 1 2 1 2 1 1 2 1 2 1 1 2 2 2 2 2 1 1 2 2 1 2 1 2 2 2 1 1 2 2 1
#> ...
#> Labels:
#>  value  label
#>      1   male
#>      2 female

library(foreign)
df_foreign<- read.spss("try.sav", to.data.frame = TRUE) 
#> re-encoding from UTF-8
class(df_foreign$gender)
#> [1] "factor"
table(df_foreign$gender)
#> 
#>   male female 
#>   1972   2417
df_foreign$gender
#>    [1] female female female male   female female female female female female
#>   [11] female female female male   female female female female female male  
#>   [21] female female female female female female male   male   male   male  
#>   [31] female female female female female female female female female female
#>   [41] male   female female male   female female female female female female
#>   [51] female female male   female female female female male   female female
#>   [61] female female female female female female female female female female
#>   [71] female female female female female female male   male   female female
#>   [81] male   female male   female male   male   female male   female male  
#>   [91] male   female female female female female male   male   female female
....
#> Levels: male female

^{由reprex package (v0.3.0) 于 2020-01-06 创建}

Answer 3

您也可以使用 Haven 包中的 as_factor()。

library(haven)
as_factor(df_foreign$gender)

应该可以！祝你好运！