【发布时间】:2011-12-26 03:24:38
【问题描述】:
我有一个使用 Akka Typed Actors 的 Java 应用程序。该代码在 Eclipse 中没有错误,但是当我启动我的应用程序时它崩溃并打印此错误:
Exception in thread "main" java.lang.VerifyError: Inconsistent stackmap frames at branch target 266 in method com.example.actors.DBActor.getItems(Lorg/joda/time/DateTime;Lorg/joda/time/DateTime;)I at offset 170
at com.example.ui.Main$1.create(Main.java:31)
at akka.actor.TypedActor$$anonfun$newInstance$3.apply(TypedActor.scala:677)
at akka.actor.TypedActor$$anonfun$newInstance$3.apply(TypedActor.scala:677)
at akka.actor.TypedActor$.newTypedActor(TypedActor.scala:847)
at akka.actor.TypedActor$$anonfun$newInstance$1.apply(TypedActor.scala:601)
at akka.actor.TypedActor$$anonfun$newInstance$1.apply(TypedActor.scala:601)
at akka.actor.LocalActorRef.akka$actor$LocalActorRef$$newActor(ActorRef.scala:1084)
at akka.actor.LocalActorRef$$anonfun$2.apply(ActorRef.scala:628)
at akka.actor.LocalActorRef$$anonfun$2.apply(ActorRef.scala:628)
at akka.util.ReentrantGuard.withGuard(LockUtil.scala:20)
at akka.actor.LocalActorRef.<init>(ActorRef.scala:628)
at akka.actor.Actor$.actorOf(Actor.scala:249)
at akka.actor.TypedActor$.newInstance(TypedActor.scala:677)
at akka.actor.TypedActor.newInstance(TypedActor.scala)
at com.example.ui.Main.main(Main.java:29)
我不明白有什么问题。我检查了我的com.example.actors.DBActor.getItems(),但没有错误。有什么问题?
更新
以下是我收到此错误的代码示例。 我在 Eclipse 的“构建路径”上有这些 jar 文件:
-
derby.jar(来自JDK7)(本例仅使用内存数据库) akka-actor-1.2.jarakka-typed-actor-1.2.jaraspectwerkz-2.2.3.jarscala-library.jar
代码如下:
import java.sql.Connection;
import java.sql.DriverManager;
import java.sql.PreparedStatement;
import java.sql.ResultSet;
import java.sql.SQLException;
import akka.actor.TypedActor;
import akka.actor.TypedActorFactory;
public class App {
public App() {
TypedActor.newInstance(Backend.class, new TypedActorFactory() {
public TypedActor create() {
return new DataActor();
}
});
}
class DataActor extends TypedActor implements Backend {
@Override
public void insertData(String msg) {
final String sqlSelect = "SELECT msg FROM SESSION.messages "+
"WHERE to_user_id = ? AND from_user_id = ?";
final String connectionURL = "jdbc:derby:memory:memdatabase;create=true";
/* if this declaration is moved to where the string is used
in the conditional, the conditional can be used */
String result;
try(Connection conn = DriverManager.getConnection(connectionURL);) {
try(PreparedStatement ps = conn.prepareStatement(sqlSelect);
ResultSet rs = new QueryHelper(ps)
.integer(13).integer(26).executeQuery();) {
/* this doesn't work */
result = (rs.next()) ? rs.getString("text")
: null;
/* but this work:
String result = (rs.next()) ? rs.getString("text")
: null;
*/
/* this works fine
while(rs.next()) {
result = rs.getString("msg");
} */
}
} catch (SQLException e) {
e.printStackTrace();
}
}
}
class QueryHelper {
private final PreparedStatement ps;
private int index = 1;
public QueryHelper(PreparedStatement ps) {
this.ps = ps;
}
public QueryHelper integer(int param) throws SQLException {
ps.setInt(index++, param);
return this;
}
public ResultSet executeQuery() throws SQLException {
return ps.executeQuery();
}
}
public interface Backend {
public void insertData(String text);
}
public static void main(String[] args) {
new App();
}
}
【问题讨论】:
-
当字节码生成的代码构建不正确时,可能会发生这种情况。我会尝试更早的版本(或更高版本)
-
@Peter:我之前有一个较早的版本,但我得到了同样的错误,但使用了不同的方法。
-
Akka
-
@ViktorKlang:可能是因为我使用的是 Java 7?我将尝试创建一个最小的程序。
-
在 Java 7 上运行时,我已经看到其他字节码增强器/修改的错误。解决方案是显式编译 Java 6 的代码:-target 1.6 in javac。
标签: java akka verifyerror try-with-resources typedactor