【问题标题】:creating and accessing dynamic column names within dplyr functions在 dplyr 函数中创建和访问动态列名
【发布时间】:2021-05-14 19:45:59
【问题描述】:
library(rlang)
library(dplyr)
library(lubridate)

example = tibble(
  date = today() + c(1:6),
  foo = rnorm(6), 
)

do.some.stuff <- function(data, foo.col){
  sum.col = parse_expr(paste(expr_text(enexpr(foo.col)), "sum", sep="."))
  max.col = parse_expr(paste(expr_text(enexpr(foo.col)), "max", sep="."))
  cnt.col = parse_expr(paste(expr_text(enexpr(foo.col)), "cnt", sep="."))
  
  select(data, date, {{ foo.col }}) %>% 
    filter(!is.na(date) & !is.na({{ foo.col }})) %>% mutate(
      "{{ foo.col }}.cnt" := cumsum( !is.na({{ foo.col }}) ),
      "{{ foo.col }}.sum" := cumsum({{ foo.col }}),
      "{{ foo.col }}.max" := cummax( {{ sum.col }} ),
      "{{ foo.col }}.mu" :=  {{ sum.col }} / {{ cnt.col }}
    )
}

do.some.stuff(example, foo)

所以上面的代码工作得很好,但是有点难看,尤其是三个parse_expr 行。我可以将函数重写为:

do.some.stuff <- function(data, foo.col){
  sum.col = paste(expr_text(enexpr(foo.col)), "sum", sep=".")
  max.col = paste(expr_text(enexpr(foo.col)), "max", sep=".")
  cnt.col = paste(expr_text(enexpr(foo.col)), "cnt", sep=".")
  
  select(data, date, {{ foo.col }}) %>% 
    filter(!is.na(date) & !is.na({{ foo.col }})) %>% mutate(
      cnt.col := cumsum( !is.na({{ foo.col }}) ),
      sum.col := cumsum({{ foo.col }}),
      max.col := cummax( {{ parse_expr(sum.col) }} ),
      "{{ foo.col }}.mu" :=  {{ parse_expr(sum.col) }} / {{ parse_expr(cnt.col) }}
    )
}

但也好不到哪里去。有没有其他方法可以完成同样的行为(我不想改变 df 的形状,那部分不取决于我)但是踢 rlang 依赖?现在这工作得很好,但如果可能的话,我想要一些更干净/更容易阅读的东西。如果不是很明显,我对 R 中的元编程很陌生,尽管我确实有其他语言的经验。

【问题讨论】:

    标签: r dplyr tidyr rlang tidyeval


    【解决方案1】:

    across.names 参数一起使用,或者如果foo_cnt 等带下划线是可以的,那么只需省略.names 参数,因为这是默认值。

    library(dplyr)
    library(tibble)
    
    do.some.stuff.2 <- function(data, col) {
      cnt <- function(x) cumsum(!is.na(x))
      mx <- function(x) cummax(cumsum(x))      
      mu <- function(x) cumsum(x) / cnt(x)
      data %>%
        select(date, {{col}}) %>%
        filter(!is.na(date) & !is.na({{col}})) %>%
        mutate(across({{col}}, lst(cnt, sum=cumsum, max=mx, mu), .names = "{.col}.{.fn}" ))
    }
    # test
    do.some.stuff.2(example, foo)
    

    给予:

    # A tibble: 6 x 6
      date             foo foo.cnt   foo.sum   foo.max    foo.mu
      <date>         <dbl>   <int>     <dbl>     <dbl>     <dbl>
    1 2021-02-11 -0.000202       1 -0.000202 -0.000202 -0.000202
    2 2021-02-12  0.363          2  0.363     0.363     0.181   
    3 2021-02-13  1.27           3  1.63      1.63      0.543   
    4 2021-02-14  1.50           4  3.13      3.13      0.781   
    5 2021-02-15  1.00           5  4.13      4.13      0.826   
    6 2021-02-16 -0.458          6  3.67      4.13      0.612 
    

    【讨论】:

    • 这是美丽的想法foo.max 是通过在foo.sum 上应用cummax 而不是foo 计算得出的
    【解决方案2】:

    这可能是一个更简单的版本

    library(rlang)
    library(dplyr)
    library(lubridate)
    
    example = tibble(
      date = today() + c(1:6),
      foo = rnorm(6), 
    )
    
    # This is your initial version of the code.
    do.some.stuff <- function(data, foo.col){
      sum.col = parse_expr(paste(expr_text(enexpr(foo.col)), "sum", sep="."))
      max.col = parse_expr(paste(expr_text(enexpr(foo.col)), "max", sep="."))
      cnt.col = parse_expr(paste(expr_text(enexpr(foo.col)), "cnt", sep="."))
      
      select(data, date, {{ foo.col }}) %>% 
        filter(!is.na(date) & !is.na({{ foo.col }})) %>% mutate(
          "{{ foo.col }}.cnt" := cumsum( !is.na({{ foo.col }}) ),
          "{{ foo.col }}.sum" := cumsum({{ foo.col }}),
          "{{ foo.col }}.max" := cummax( {{ sum.col }} ),
          "{{ foo.col }}.mu" :=  {{ sum.col }} / {{ cnt.col }}
        )
    }
    
    # Here is my version where foo.col is a character param
    do.some.stuff_2 <- function(data, foo.col) {
      data %>% select(date, !!foo.col) %>% 
        filter(!is.na(date) & !is.na(!!foo.col)) %>%
        mutate(
          # Here as foo.col is a character to add new column just combine them together
          !!paste0(foo.col, ".cnt") := cumsum(!is.na(.data[[foo.col]])),
          !!paste0(foo.col, ".sum") := cumsum(.data[[foo.col]]),
          !!paste0(foo.col, ".max") := cummax(.data[[paste0(foo.col, ".sum")]]),
          !!paste0(foo.col, ".mu") :=  .data[[paste0(foo.col, ".sum")]] / 
                                       .data[[paste0(foo.col, ".cnt")]]
        )
    }
    
    identical(do.some.stuff(example, foo), do.some.stuff_2(example, "foo"))
    

    您可以在这里了解更多信息:https://dplyr.tidyverse.org/articles/programming.html

    【讨论】:

    • 直接访问.data是不是不被接受?我不熟悉 R 的特定约定或礼节,但在许多其他语言中,直接访问点或下划线变量会被视为违反封装而被反对。这种行为对于 dplyr 是否正常?
    • 您可以在此处查看更多文档。 .datadplyr dplyr.tidyverse.org/articles/programming.html 的内部引用
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