我需要根据 SQL 中的 COUNT 函数从表中选择记录答案

【问题标题】：I need to SELECT records from a table based on a COUNT function in SQL我需要根据 SQL 中的 COUNT 函数从表中选择记录
【发布时间】：2013-10-29 09:15:32
【问题描述】：

我有四张桌子：

  PAINTING            GALLERY             ARTIST              PAINTED
- PAINTING_TITLE    - GALLERY_ID        - ARTIST_ID         - PAINTED_CODE
- PAINTING_ID       - GALLERY_NAME      - ARTIST_LAST       - ARTIST_ID
                                        - ARTIST_FIRST      - PAINTING_ID

PAINTED 表会记录每位艺术家绘制的画作。有些画是由不止一位艺术家绘制的。我想返回两位艺术家绘制的画作列表。

SELECT PAINTING.PAINTING_TITLE AS TITLE, 
   GALLERY.GALLERY_NAME AS GALLERY, 
   ARTIST.ARTIST_FIRST AS ARTISTFIRST, 
   ARTIST.ARTIST_LAST AS ARTISTLAST
FROM PAINTING, GALLERY, PAINTED, ARTIST
WHERE PAINTING.GALLERY_ID = GALLERY.GALLERY_ID
AND PAINTING.PAINTING_ID = PAINTED.PAINTING_ID
AND ARTIST.ARTIST_ID = PAINTED.ARTIST_ID
AND (SELECT COUNT(*) FROM PAINTED, PAINTING, ARTIST
WHERE PAINTING.GALLERY_ID = GALLERY.GALLERY_ID
AND PAINTING.PAINTING_ID = PAINTED.PAINTING_ID
AND ARTIST.ARTIST_ID = PAINTED.ARTIST_ID) = 2;

这不会返回我需要的结果。你对如何只选择有两位艺术家的画作有什么想法吗？

我正在使用 Access SQL，任何帮助将不胜感激。

【问题讨论】：

标签： sql select count

【解决方案1】：

使用GROUP BY 而不是内部SELECT：

SELECT
    PAINTING.PAINTING_TITLE AS TITLE, 
    GALLERY.GALLERY_NAME AS GALLERY
FROM
    PAINTING,
    GALLERY,
    PAINTED
WHERE
        PAINTING.GALLERY_ID = GALLERY.GALLERY_ID
    AND
        PAINTING.PAINTING_ID = PAINTED.PAINTING_ID
GROUP BY
    PAINTING.PAINTING_TITLE,
    GALLERY.GALLERY_NAME
HAVING
    COUNT(PAINTED.ARTIST_ID) = 2

【讨论】：

我不是 Access SQL 方面的专家……但不应该把这个条件移到 having 子句中吗？
@canon 当然应该。很好发现。
不错的解决方案，但它没有在画作旁边列出艺术家的名字。你知道我怎样才能让这方面发挥作用吗？