Oracle SQL 周年日期查询

Question

我需要一些帮助来创建一个显示企业员工周年纪念日的查询。我需要在我选择的两个日期内运行报告并显示结果。我希望报告也显示历史周年数据。

我想要列 NAME、ANNIVERSARY DATE、YEARS WITH BUSINESS

我在数据集中的列是姓名和工作日期。

感谢任何帮助！

TIA

Answer 1

使用MONTHS_BETWEEN 和ADD_MONTHS：

SELECT name,
       date_of_employment,
       ADD_MONTHS(
         date_of_employment,
         (EXTRACT(YEAR FROM SYSDATE) - EXTRACT(YEAR FROM date_of_employment))*12
       ) AS anniversary,
       MONTHS_BETWEEN(SYSDATE, date_of_employment)/12
         AS years_with_business,
       TRUNC(MONTHS_BETWEEN(SYSDATE, date_of_employment)/12)
         AS full_years_with_business
FROM   table_name;

其中，对于样本数据：

CREATE TABLE table_name ( name, date_of_employment ) AS
SELECT 'Alice',   ADD_MONTHS(TRUNC(SYSDATE - 1), -120) FROM DUAL UNION ALL
SELECT 'Beryl',   ADD_MONTHS(TRUNC(SYSDATE + 0), -120) FROM DUAL UNION ALL
SELECT 'Carol',   ADD_MONTHS(TRUNC(SYSDATE + 1), -120) FROM DUAL UNION ALL
SELECT 'Debra',   ADD_MONTHS(TRUNC(SYSDATE - 1),  +12) FROM DUAL UNION ALL
SELECT 'Emma',    ADD_MONTHS(TRUNC(SYSDATE + 0),  +12) FROM DUAL UNION ALL
SELECT 'Frances', ADD_MONTHS(TRUNC(SYSDATE + 1),  +12) FROM DUAL;

输出：

NAME	DATE_OF_EMPLOYMENT	ANNIVERSARY	YEARS_WITH_BUSINESS	FULL_YEARS_WITH_BUSINESS
Alice	2011-08-18 00:00:00	2021-08-18 00:00:00	10.00435082511947431302270011947431302267	10
Beryl	2011-08-19 00:00:00	2021-08-19 00:00:00	10	10
Carol	2011-08-20 00:00:00	2021-08-20 00:00:00	9.99897448103345280764635603345280764633	9
Debra	2022-08-18 00:00:00	2021-08-18 00:00:00	-.9956491748805256869772998805256869773	0
Emma	2022-08-19 00:00:00	2021-08-19 00:00:00	-1	-1
Frances	2022-08-20 00:00:00	2021-08-20 00:00:00	-1.00102551896654719235364396654719235364	-1

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