如何将两个sql语句的结果连接到一个表和不同的列中答案

【问题标题】：How to join result of two sql statements into one table and different columns如何将两个sql语句的结果连接到一个表和不同的列中
【发布时间】：2012-10-06 22:31:00
【问题描述】：

我有三个选择查询，它们根据不同的 where 子句从同一张表中返回总记录、成功记录和失败记录。我想将所有这些语句的结果合并到一个表中以创建我的存储过程，但结果表应具有 cdr 、 success 、 failure 三个不同的列

SELECT Count(*) AS cdr 
FROM   ABC AS c WITH (NOLOCK) 
WHERE  APPID IN( 1, 2 ) 
       AND CALLDATE = '2012-10-09' 

SELECT Count(*) AS success 
FROM   ABC AS d WITH (NOLOCK) 
WHERE  APPID IN( 44, 45 ) 
       AND CALLDATE = '2012-10-09' 
       AND HANGUPCODE IN ( 'man', 'mach' ) 

SELECT Count(*) AS fail 
FROM   ABC WITH (NOLOCK) 
WHERE  APPID IN( 44, 45 ) 
       AND CALLDATE = '2012-10-09' 
       AND HANGUPCODE NOT IN ( 'man', 'mach' )

Union 在一列中给出结果，所以它不起作用。任何其他想法

【问题讨论】：

我不明白，你想要一个只有一行 3 列的结果集吗？

标签： sql sql-server stored-procedures

【解决方案1】：

只需将每个 select 语句括在括号中，给每个 select 语句一个别名，并在顶部使用 SELECT：

SELECT 
  (select count(*) as cdr  
   from abc as c with (nolock) 
   where appid in(1,2)  and calldate = '2012-10-09'
  ) AS Column1,  
  (select count(*) as success  
   from abc as d with (nolock) 
   where appid in(44,45) and calldate = '2012-10-09' 
       and hangupcode in ('man', 'mach')
  ) AS Column2, 
  (select count(*) as fail  
   from abc  with (nolock) 
   where appid in(44,45) and calldate = '2012-10-09' 
       and hangupcode not in  ('man', 'mach')
  ) AS Column3

基本上，您将每个查询视为一个单独的列。

【讨论】：

【解决方案2】：

  SELECT a.cdr, b.success, c.failure FROM 
  (SELECT count(*) AS cdr  
   FROM abc as c WITH (NOLOCK) 
   WHERE appid IN (1,2) AND
         calldate = '2012-10-09'
  ) AS a,   
  (SELECT count(*) AS success  
   FROM abc AS d WITH (NOLOCK) 
   WHERE appid IN (44,45) AND 
         calldate = '2012-10-09' AND 
         hangupcode IN ('man', 'mach')
  ) AS b,  
  (SELECT count(*) AS fail  
   FROM abc WITH (NOLOCK) 
   WHERE appid IN (44,45) AND
         calldate = '2012-10-09' AND 
         hangupcode NOT IN ('man', 'mach')
  ) AS c

【讨论】：

【解决方案3】：

select a.cdr, b.success, c.fail from
( select count(*) as cdr  
from abc as c with (nolock) where appid in(1,2)  
and calldate = '2012-10-09' ) a
, ( select count(*) as success  
from abc as d with (nolock) where appid in(44,45)  
and calldate = '2012-10-09'
and hangupcode in ('man', 'mach') ) b
, ( select count(*) as fail  from abc  with (nolock) where appid in(44,45) and calldate = '2012-10-09'and hangupcode not in  ('man', 'mach') ) c

【讨论】：

【解决方案4】：

select
   sum(case when appid in(1,2) and calldate = '2012-10-09' then 1 else 0 end) as cdr,
   sum(case when appid in(44,45) and calldate = '2012-10-09'and hangupcode in ('man', 'mach') then 1 else 0 end) as success,
   sum(case when appid in(44,45) and calldate = '2012-10-09'and hangupcode not in  ('man', 'mach') then 1 else 0 end)as fail
from abc

【讨论】：