Sequelize：列名小写不适用于包含的模型

Question

我有两个模型：类别和书签。书签通过 categoryId 列与类别关联。

类别也有name、createdAt、orderId列；

---

我可以通过以下方式获取类别及其所有书签：

const category = await Category.findOne({
    where: { id: req.params.id },
    include: [
      {
        model: Bookmark,
        as: 'bookmarks'
      },
    ]
  });

---

但现在我想更改书签的排序方式。订单类型可以是name、createdAt或orderId；

const order = orderType == 'name'
  ? [[
      { model: Bookmark, as: 'bookmarks' },
      Sequelize.fn('lower', Sequelize.col('bookmarks.name')),
      'ASC'
    ]]
  : [[{ model: Bookmark, as: 'bookmarks' }, orderType, 'ASC']]

const category = await Category.findOne({
    where: { id: req.params.id },
    include: [
      {
        model: Bookmark,
        as: 'bookmarks'
      },
    ],
    order
  });

orderType 为createdAt 或orderId 时工作正常，但在name 时失败

---

我收到此错误：SQLITE_ERROR: near \"(\": syntax error 和 Sequelize 生成的 SQL 查询是：

SELECT `Category`.`id`, `Category`.`name`, `bookmarks`.`id` AS `bookmarks.id`, `bookmarks`.`name` AS `bookmarks.name`, `bookmarks`.`categoryId` AS `bookmarks.categoryId`, `bookmarks`.`orderId` AS `bookmarks.orderId`, `bookmarks`.`createdAt` AS `bookmarks.createdAt`
FROM `categories` AS `Category`
INNER JOIN `bookmarks` AS `bookmarks` ON `Category`.`id` = `bookmarks`.`categoryId`
ORDER BY `bookmarks`.lower(`bookmarks`.`name`) ASC;

Answer 1

改成：

const order =
    orderType == 'name'
      ? [[Sequelize.fn('lower', Sequelize.col('bookmarks.name')), 'ASC']]
      : [[{ model: Bookmark, as: 'bookmarks' }, orderType, 'ASC']];

现在它正在工作。