正确连接查询 - SQL

Question

我有两个名为Books 和Co-author 的表。我想加入他们以使表格显示在“所需的输出”下。我是 SQL 新手，我正在努力加入我所做的两个查询...

书籍：

ISBN	title	author
1111	Book1	author1
2222	Book2	author2
3333	Book3
4444	Book4	author3

合著者：

id	author	book(isbn)
1	author_x	4444
2	author_y	1111
3	author_z	2222
4	author_w	4444

期望的输出：

title	has_author	count_co_author
Book1	1	1
Book2	1	1
Book3	0	0
Book4	1	2

我有以下疑问：

SELECT b.title, count(c.book)
FROM Books b
LEFT JOIN Coauthor c ON b.isbn = c.book
GROUP BY b.title

返回列count_co-author。

另一个查询列has_author：

SELECT 
    b.title, 
    CASE 
        WHEN b.author IS NULL 
            THEN 0 
            ELSE 1 
    END AS 'Has author'
FROM Books b

如何组合它们？

Answer 1

选择书籍并加入合著者人数：

select
  b.title,
  case when b.author is null then 0 else 1 end as has_author,
  coalesce(c.cnt, 0) as count_co_author
from books b
left outer join
(
  select book, count(*) as cnt
  from co_author
  group by book
) c on c.book = b.isbn
order by b.title;

或从书籍中选择并在子查询中获取共同作者数：

select
  b.title,
  case when b.author is null then 0 else 1 end as has_author,
  (
    select count(*)
    from co_author c
    where c.book = b.isbn
  ) as count_co_author
from books b
order by b.title;

Answer 2

SELECT 
    b.title, 
    CASE
        WHEN b.author IS NULL
            THEN 0
            ELSE 1
    END AS has_author,
    count(c.book) as count-coauthor
FROM
    Books b
LEFT JOIN
    Coauthor c
ON
    b.isbn = c.book
GROUP BY
    b.title

应该在 IG 上工作

Answer 3

select  title, has_auther, count_co-author, 
from 
( 
  (
    SELECT
      b.title,
      count(c.book) as count_co-author
    FROM Books b 
    LEFT JOIN Coauthor c ON b.isbn = c.book
    GROUP BY b.title
  ) as t1, 
  (
    SELECT 
      b.title, 
      CASE WHEN b.author IS NULL 
        THEN 0 
        ELSE 1 
    END AS has_auther
    FROM Books b
  ) as t2
)

试试这个