SQL Group by With Case答案

【问题标题】：SQL Group by With CaseSQL Group by With Case
【发布时间】：2025-12-23 10:00:12
【问题描述】：

Name |  Amount | Date
_____________________
Jacob | 15 |    1-Oct-16

Jacob | 50 |    2-Oct-16

Ethan | 24 |    3-Oct-16

Jacob | 30 |    3-Oct-16

William |   17 |    1-Oct-16

William |   11 |    2-Oct-16

Ethan | 36 |    3-Oct-16

Ethan | 9 | 1-Oct-16

我有上面的表格，我想要过去 5 天的总和，比如

Name | 5-oct-16 | 4-oct-16 | 3-oct-16 | 2-oct-16| 1-oct-16 
___________________________________________________________

Jacob | 0       | 0        |30         | 50        | 15
Ethan | 0       | 0        |60         | 0        | 9
William | 0       | 0        |0         | 11        | 17

想按名称分组，过去 5 天的总和相隔。

【问题讨论】：

标签： sql sql-server sql-server-2008 group-by

【解决方案1】：

我想你想要条件聚合：

SELECT Name,
       SUM(CASE DATE WHEN '2016-10-05' THEN Amount ELSE 0 END) as amount_2016105,
       SUM(CASE DATE WHEN '2016-10-04' THEN Amount ELSE 0 END) as amount_2016104,
       SUM(CASE DATE WHEN '2016-10-03' THEN Amount ELSE 0 END) as  amount_2016103,
       SUM(CASE DATE WHEN '2016-10-02' THEN Amount ELSE 0 END) as  amount_2016102,
       SUM(CASE DATE WHEN '2016-10-01' THEN Amount ELSE 0 END) as  amount_2016101
FROM MyTable
GROUP BY Name;

【讨论】：