Postgresql 到雪花

Question

我很难将以下 postgres 代码转换为雪花。请有经验的人帮我解决这个问题好吗？

1. 选择 count(distinct inv.invite_id) filter (where invite_opened) "Invites Opened"

2. 选择 b.onboard_initial_agents_invited_at 然后是“Initial Agents Invited”时的情况

   谢谢，

   哈比

   对于第一个，我尝试了这个，但没有用：

   选择 count(distinct inv.invite_id) case when 'invites_opened' THEN 1 END as "Invites Opened"

Answer 1

select count(distinct inv.invite_id) filter (where invite_opened) "Invites Opened" 是条件聚合：

select count(distinct CASE WHEN invite_opened THEN inv.invite_id END) AS "Invites Opened"

它也可以通过使用 COUNT_IF（但没有 DISTINCT）来实现：

select count_if(invite_opened) AS "Invites Opened"