将两个变量作为两列导出到 CSV 文件答案

【问题标题】：Export Two Variables as Two Columns to CSV File将两个变量作为两列导出到 CSV 文件
【发布时间】：2023-01-20 01:58:52
【问题描述】：

我创建了两个变量，它们从特定文件中选取多个值。这是我的脚本的一部分：

#Identifying the AccountList.ain File Path
$AccountListPath = "$CADstreamDataPATH\ADM\AccountList.ain"

#Create Variable for User Description & User ID
[xml]$UserInfoPath = gc $AccountListPath
$UserDescString = $UserInfoPath.AccountList.UserAccount.description
$UserInfoString = $UserInfoPath.AccountList.UserAccount.UserInfo.username

#Create User Description List & User Info (User ID) List
$UserDescObject = $UserDescString | Select-Object @{Name='Description';Expression={$_}}
$UserInfoObject = $UserInfoString | Select-Object @{Name='UserID';Expression={$_}}

这些是 $UserDescObject 变量的结果：

这些是 $UserInfoObject 变量的结果：

我正在尝试将 $UserDescObject 变量作为第 1 列和 $UserInfoObject 作为第 2 列导出到 csv。

我尝试了两种不同的方法（对我来说都失败了）。

方法 #1：导出为 CSV $UserDescObject，然后附加 $UserInfoObject

这是我添加到上面脚本的附加部分：

#Identifying the AccountList.ain File Path
$AccountListPath = "$CADstreamDataPATH\ADM\AccountList.ain"

#Create Variable for User Description & User ID
[xml]$UserInfoPath = gc $AccountListPath
$UserDescString = $UserInfoPath.AccountList.UserAccount.description
$UserInfoString = $UserInfoPath.AccountList.UserAccount.UserInfo.username

#Export to CSV
$UserDescObject = $UserDescString | Select-Object @{Name='Description';Expression={$_}}
$UserDescObject | Export-Csv .\LDAPCrossWalkTable.csv -Force -NoType
$UserInfoObject = $UserInfoString | Select-Object @{Name='UserID';Expression={$_}}
$UserInfoObject | Export-Csv .\LDAPCrossWalkTable.csv -Append -NoTypeInformation

这是我在运行脚本后看到的错误：

方法 #2：导出到 CSV $UserDescObject，导入创建的 CSV，并附加 $UserInfoObject

#Identifying the AccountList.ain File Path
$AccountListPath = "$CADstreamDataPATH\ADM\AccountList.ain"

#Create Variable for User Description & User ID
[xml]$UserInfoPath = gc $AccountListPath
$UserDescString = $UserInfoPath.AccountList.UserAccount.description
$UserInfoString = $UserInfoPath.AccountList.UserAccount.UserInfo.username

#Create User Description List & User Info (User ID) List
$UserDescObject = $UserDescString | Select-Object @{Name='Description';Expression={$_}}
$UserInfoObject = $UserInfoString | Select-Object @{Name='UserID';Expression={$_}}

#Export User Description & User Info (User ID) Lists to CSV
$UserDescObject | Export-Csv .\LDAPCrossWalkTable.csv -Force -NoType
$ImportCSV = Import-CSV .\LDAPCrossWalkTable.csv
$ImportCSV | Select-Object *,@{Name='UserInfo';Expression={$UserInfoObject}} | Export-Csv .\LDAPCrossWalkTable.csv -NoTypeInformation

我几乎能够让两列都正确显示。我收到了两列。然而，$UserInfoObject 中的所有文本行都被添加到 CSV 文件的每一行中，而不是正确地分开：

这是我想要在 csv 文件中显示的内容：

非常感谢任何输入！

【问题讨论】：

标签： powershell csv export-to-csv powershell-5.1

【解决方案1】：

我能够使用数组解决购买问题。这是脚本：

#Identifying the AccountList.ain File Path
$AccountListPath = "$CADstreamDataPATHADMAccountList.ain"

#Create Variable for User Description & User ID
[xml]$UserInfoPath = gc $AccountListPath
$UserDescString = $UserInfoPath.AccountList.UserAccount.description
$UserInfoString = $UserInfoPath.AccountList.UserAccount.UserInfo.username

#Combine Description & Info as well as Export to CSV
$arr = @()
for ($i = 0; $i -lt $UserDescString.length; $i++) {
    $arr += [pscustomobject]@{Descripton=$UserDescString[$i];UserID=$UserInfoString[$i]}
}
$arr | Export-Csv .LDAPCrossWalkTable.csv -Force -NoTypeInformation

【讨论】：