获取第一个开始时间和最后一个结束时间

Question

我在第一张图片中有一个初始查询结果。

select 
    rpt_mem.Member_Full_Name as Member,
    rpt_mem.Email_Address as [Work Email],
    CONVERT(VARCHAR(10), Date_Time_Start, 101) as [Shift Start Date],
    MIN(CONVERT(VARCHAR(5), Date_Time_Start, 108)) as [Shift Start Time],
    CONVERT(VARCHAR(10), Date_Time_End, 101) as [Shift End Date],
    MAX(CONVERT(VARCHAR(5), Date_Time_End, 108)) as [Shift End Time]
from Schedule
where rpt_mem.Member_Full_Name = 'Member1'
AND CONVERT(VARCHAR(10), Date_Time_Start, 101) = '10/04/2020'

如何修改查询以仅获取第一个班次开始时间和最后一个结束时间，如第二张图片

Answer 1

你也可以这样做-

select 
    rpt_mem.Member_Full_Name as Member,
    rpt_mem.Email_Address as [Work Email],
    CONVERT(VARCHAR(10), MIN(Date_Time_Start), 101) as [Shift Start Date],
    CONVERT(VARCHAR(5), MIN(Date_Time_Start), 108) as [Shift Start Time],
    CONVERT(VARCHAR(10), MAX(Date_Time_End), 101) as [Shift End Date],
    CONVERT(VARCHAR(5), MAX(Date_Time_End), 108) as [Shift End Time]
from Schedule rpt_mem
where rpt_mem.Member_Full_Name = 'Member1'
AND CONVERT(VARCHAR(10), Date_Time_Start, 101) = '04/10/2020'
GROUP BY 
 rpt_mem.Member_Full_Name,
 rpt_mem.Email_Address;

这是一个 db fiddle 链接 - https://dbfiddle.uk/?rdbms=sqlserver_2019&fiddle=61da8cab5471d21818eb5b7fec8d509c

Answer 2

您只需要group by Date_Time_Start 和Date_Time_End 的日期部分。

declare @Schedule table (Member varchar(8), Date_Time_Start datetime2(0), Date_Time_End datetime2(0))

insert into @Schedule (Member, Date_Time_Start, Date_Time_End)
values
('Member 1', '10 Apr 2020 12:00:00', '10 Apr 2020 14:00')
, ('Member 1', '10 Apr 2020 17:00:00', '10 Apr 2020 18:00')

select 
    , CONVERT(VARCHAR(10), convert(date,S.Date_Time_Start), 101) as [Shift Start Date]
    , CONVERT(VARCHAR(5), MIN(S.Date_Time_Start), 108) as [Shift Start Time]
    , CONVERT(VARCHAR(10), convert(date,S.Date_Time_Start), 101) as [Shift End Date]
    , CONVERT(VARCHAR(5), MAX(S.Date_Time_End), 108) as [Shift End Time]
from @Schedule S
where S.Member in ('Member 1')
--AND CONVERT(VARCHAR(10), Date_Time_Start, 101) = '10/04/2020'
-- Sargeable i.e. can make use of indexes.
AND S.Date_Time_Start >= '10 Apr 2020'
AND S.Date_Time_Start < '11 Apr 2020'
group by S.Member, convert(date,S.Date_Time_Start), convert(date,S.Date_Time_End);

返回：

Member      Shift Start Date    Shift Start Time    Shift End Date  Shift End Time
Member 1    04/10/2020          12:00               04/10/2020      18:00

注意事项：

1. 您不想在where 子句中转换您的Date_Time_Start，因为它是不可分割的。而是使用窗口条件。

2. 您希望养成使用明确日期格式的习惯。

3. 如果您愿意，此查询将允许您运行多天和多个成员。您只需要添加任何其他成员信息列，例如电邮至group by。

4. 如果您使用 DDL/DML 语句设置测试数据，如图所示，您可以让人们更容易回答您的问题。