【问题标题】:Javascript If statement changes the outcome of pushing previous variable to an arrayJavascript If 语句更改将前一个变量推送到数组的结果
【发布时间】:2023-01-18 23:05:19
【问题描述】:

在这里我使用了 Luhn 算法来验证信用卡号是否有效。 validateCred 函数运行良好,但在第二个函数中,我只想将无效 CC 编号的数组添加到 invalidCCN 数组中。但是由于某种原因而不是确切的 CC 编号数组,arr 变量被推入了 invalidCCN。我试过通过它的索引和它本身访问它,但两者都不起作用!

// All valid credit card numbers
const valid1 = [4, 5, 3, 9, 6, 7, 7, 9, 0, 8, 0, 1, 6, 8, 0, 8]
const valid2 = [5, 5, 3, 5, 7, 6, 6, 7, 6, 8, 7, 5, 1, 4, 3, 9]
const valid3 = [3, 7, 1, 6, 1, 2, 0, 1, 9, 9, 8, 5, 2, 3, 6]
const valid4 = [6, 0, 1, 1, 1, 4, 4, 3, 4, 0, 6, 8, 2, 9, 0, 5]
const valid5 = [4, 5, 3, 9, 4, 0, 4, 9, 6, 7, 8, 6, 9, 6, 6, 6]

// All invalid credit card numbers
const invalid1 = [4, 5, 3, 2, 7, 7, 8, 7, 7, 1, 0, 9, 1, 7, 9, 5]
const invalid2 = [5, 7, 9, 5, 5, 9, 3, 3, 9, 2, 1, 3, 4, 6, 4, 3]
const invalid3 = [3, 7, 5, 7, 9, 6, 0, 8, 4, 4, 5, 9, 9, 1, 4]
const invalid4 = [6, 0, 1, 1, 1, 2, 7, 9, 6, 1, 7, 7, 7, 9, 3, 5]
const invalid5 = [5, 3, 8, 2, 0, 1, 9, 7, 7, 2, 8, 8, 3, 8, 5, 4]

// Can be either valid or invalid
const mystery1 = [3, 4, 4, 8, 0, 1, 9, 6, 8, 3, 0, 5, 4, 1, 4]
const mystery2 = [5, 4, 6, 6, 1, 0, 0, 8, 6, 1, 6, 2, 0, 2, 3, 9]
const mystery3 = [6, 0, 1, 1, 3, 7, 7, 0, 2, 0, 9, 6, 2, 6, 5, 6, 2, 0, 3]
const mystery4 = [4, 9, 2, 9, 8, 7, 7, 1, 6, 9, 2, 1, 7, 0, 9, 3]
const mystery5 = [4, 9, 1, 3, 5, 4, 0, 4, 6, 3, 0, 7, 2, 5, 2, 3]

// An array of all the arrays above
const batch = [valid1, valid2, valid3, valid4, valid5, invalid1, invalid2, invalid3, invalid4, invalid5, mystery1, mystery2, mystery3, mystery4, mystery5]


// Add your functions below:


const validateCred = array => {
  // console.log('before')
  // console.log(array)
  let arr = array
  for (let x = arr.length - 2; x >= 0; x -= 2) {
    arr[x] = arr[x] * 2
    if (arr[x] > 9) {
      arr[x] = arr[x] - 9
    }
  }
  // console.log('after')
  // console.log(arr)
  const sum = arr.reduce((a, b) => a + b, 0)
  if (sum % 10 === 0) {
    return true
  } else {
    return false
  }

}

const findInvalidCards = array => {
  let invalidCCN = []
  for (let x = 0; x < array.length; x++) {
    if (!validateCred(array[x])) {
      invalidCCN.push(array[x])
    }
  }
  // array.forEach(ccNumber => {
  //     if (!validateCred(ccNumber)) {
  //         console.log(false)
  //         invalidCCN.push(ccNumber)
  //     }
  // })
  console.log(invalidCCN)
}

findInvalidCards(batch)

预期结果:

[
  4, 5, 3, 2, 7, 7,
  8, 7, 7, 1, 0, 9,
  1, 7, 9, 5
] [
  5, 7, 9, 5, 5, 9,
  3, 3, 9, 2, 1, 3,
  4, 6, 4, 3
] [
  3, 7, 5, 7, 9, 6,
  0, 8, 4, 4, 5, 9,
  9, 1, 4
] [
  6, 0, 1, 1, 1, 2,
  7, 9, 6, 1, 7, 7,
  7, 9, 3, 5
] [
  5, 3, 8, 2, 0, 1,
  9, 7, 7, 2, 8, 8,
  3, 8, 5, 4
] [
  3, 4, 4, 8, 0, 1,
  9, 6, 8, 3, 0, 5,
  4, 1, 4
] [
  6, 0, 1, 1, 3, 7, 7,
  0, 2, 0, 9, 6, 2, 6,
  5, 6, 2, 0, 3
] [
  4, 9, 2, 9, 8, 7,
  7, 1, 6, 9, 2, 1,
  7, 0, 9, 3
]

因为这些不是有效的信用卡号码。 相反,结果是:

[
    8, 5, 6, 2, 5, 7,
    7, 7, 5, 1, 0, 9,
    2, 7, 9, 5
  ],
  [
    1, 7, 9, 5, 1, 9,
    6, 3, 9, 2, 2, 3,
    8, 6, 8, 3
  ],
  [
    3, 5, 5, 5, 9, 3,
    0, 7, 4, 8, 5, 9,
    9, 2, 4
  ],
  [
    3, 0, 2, 1, 2, 2,
    5, 9, 3, 1, 5, 7,
    5, 9, 6, 5
  ],
  [
    1, 3, 7, 2, 0, 1,
    9, 7, 5, 2, 7, 8,
    6, 8, 1, 4
  ],
  [
    3, 8, 4, 7, 0, 2,
    9, 3, 8, 6, 0, 1,
    4, 2, 4
  ],
  [
    6, 0, 1, 2, 3, 5, 7,
    0, 2, 0, 9, 3, 2, 3,
    5, 3, 2, 0, 3
  ],
  [
    8, 9, 4, 9, 7, 7,
    5, 1, 3, 9, 4, 1,
    5, 0, 9, 3
  ]
]

结果是在 validateCred 中进行 for 循环后的数组,即使我没有返回它们。

【问题讨论】:

    标签: javascript arrays for-loop if-statement


    【解决方案1】:

    您正试图将整个数组推入 invalidCCN 数组。您应该推送无效数组的索引而不是整个数组。 您可以更改此行:

    invalidCCN.push(array[x])
    

    对此:

    invalidCCN.push(x)
    

    这会将无效数组的索引推入 invalidCCN 数组而不是整个数组。如果要访问无效数组,可以使用此索引从批处理数组中访问它。

    batch[invalidCCN[0]]
    

    请记住,这将为您提供批处理中无效数组的索引,而不是数组本身。

    【讨论】:

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