【发布时间】:2023-01-11 17:39:14
【问题描述】:
大家好,我是 php 的新手,我无法弄清楚为什么我会收到错误消息 我已经在上面声明了变量,并且我正在根据 if 条件填充变量的值,即使在执行 if 循环时填充了变量,错误仍然存在
以下是我的 PHP 代码
<?php
$myname;
if(isset($_POST["NWMovies"]) ){
echo "Now Showing Movies";
$myname='Now showing movies';
}if(isset($_POST["UpMovies"]) ){
echo "".$_POST["UpMovies"];
$myname='Now showing movies';
}
$connect=mysqli_connect($servername,$username,$password,$Database);
if ($connect->connect_error) {
die("Connection failed: " . $connect->connect_error);
}else{
if(isset($_POST["submit"])){
$MovieName=$_POST["Moviename"];
$MovieGenre=$_POST["MovieGenre"];
$MovieLength=$_POST["MovieLength"];
$DirectorName=$_POST["DirectorName"];
$TrailerLink=$_POST["TrailerLink"];
$ReleaseDate=date('Y-m-d',strtotime($_POST["ReleaseDate"]));
$MovieImage=addslashes(file_get_contents($_FILES['MovieImage']['tmp_name']));
$MoviePoster=addslashes(file_get_contents($_FILES["MoviePoster"]['tmp_name']));
$crew=$_POST["Crew"];
$cast=$_POST["cast"];
$crewname="";
$castname="";
foreach($crew as $key ){
$crewname.=$key.",";
}
foreach($cast as $key ){
$castname.=$key.",";
}
hear i am getting error-> $sql="insert into movies values('','$MovieName','$MovieGenre','$MovieLength','$DirectorName','$TrailerLink','$castname','$crewname','$ReleaseDate','English','$myname','$MovieImage','$MoviePoster');";
// $sql2="insert into adminlogin values ('','$mystatus','34574f');";
// $sql="insert into image value('$MovieImage');";
if ($connect->query($sql) === TRUE) {
echo "New record created successfully";
} else {
echo "Error: " . $sql . "<br>" . $connect->error;
}
}
}
?>
【问题讨论】:
-
尝试像 $myname=""; 这样初始化而不是 $myname;这会起作用
-
$我的名字;不是正确的初始化,你需要指定它的类型,例如 $my name =""';用于空字符串初始化
-
请验证
$_POST['NWMovies']或$_POST['UpMovies']是否已实际设置。你也开放SQL injections
标签: php