【发布时间】:2021-08-03 18:22:50
【问题描述】:
我们尝试输入的是字段,我们选择在 atmept 中手动插入 cart_id,以便将同一个购物车用于多个项目,例如商店:
BEGIN;
INSERT INTO cart_tb(cart_id, inventory_id, desired_amount, row_status)
VALUES
(1, 1, 2, 1),
(2, 3, 1, 1),
(2, 1, 1, 1);
END;
基本上它应该如何工作是我只能有 1 个 cart_id 但有多个库存 id (inv_id),但 Inv_id 和 cart_id 的组合应该是唯一的,所以我可以拥有不同的购物车,它们可以像现实世界中一样拥有相同的物品情况。 这是我当前的表:
CREATE TABLE public.cart_tb
(
cart_id integer NOT NULL GENERATED BY DEFAULT AS IDENTITY ( INCREMENT 1 START 1 MINVALUE 1 MAXVALUE 2147483647 CACHE 1 ),
inventory_id integer NOT NULL,
desired_amount integer NOT NULL,
row_status integer NOT NULL,
CONSTRAINT "cart_PK" PRIMARY KEY (cart_id),
CONSTRAINT "cart_UK" UNIQUE (cart_id, inventory_id),
CONSTRAINT "cart_inventory_FK" FOREIGN KEY (inventory_id)
REFERENCES public.inventory_tb (inventory_id) MATCH SIMPLE
ON UPDATE NO ACTION
ON DELETE NO ACTION
)
TABLESPACE pg_default;
ALTER TABLE public.cart_tb
OWNER to postgres;
关于如何解决此问题的任何建议?我不断遇到密钥冲突..
ERROR: duplicate key value violates unique constraint "cart_PK"
DETAIL: Key (cart_id)=(2) already exists.
SQL state: 23505
【问题讨论】:
标签: sql postgresql database-design