有条件地替换特定变量 2 的因子变量 1 的水平

Question

在我的例子中：

# Packages
library(dplyr)

# My dataset
FARM <- c(rep("LIBERTY2",4),rep("OLDOAK",4))
AGE <- c(8,9,10,10,8,9,10,10)
Y = c(0,0,0,0,1,1,1,1)
DS_F <- data.frame(FARM=FARM,AGE=AGE,Y=Y)
str(DS_F)
# 'data.frame': 8 obs. of  3 variables:
#  $ FARM: chr  "LIBERTY2" "LIBERTY2" "LIBERTY2" "LIBERTY2" ...
#  $ AGE : num  8 9 10 10 8 9 10 10
#  $ Y   : num  0 0 0 0 1 1 1 1

我只想在LIBERTY2变量FARM中使用条件变异并在另一个变量中使用规则：如果AGE等于10而不是3，如果AGE等于9而不是2，如果AGE 等于 8 比 1。

My final output should be:
DS_F2
#       FARM AGE Y
# 1 LIBERTY2   1 0
# 2 LIBERTY2   2 0
# 3 LIBERTY2   3 0
# 4 LIBERTY2   3 0
# 5   OLDOAK   8 1
# 6   OLDOAK   9 1
# 7   OLDOAK  10 1
# 8   OLDOAK  10 1

请帮我。

Answer 1

您可以将 recode() 包围为 if_else()。

library(dplyr)

DS_F %>%
  mutate(AGE.2 = if_else(FARM == "LIBERTY2",
                         recode(AGE, `10` = 3, `9` = 2, `8` = 1),
                         AGE))

#       FARM AGE Y AGE.2
# 1 LIBERTY2   8 0     1
# 2 LIBERTY2   9 0     2
# 3 LIBERTY2  10 0     3
# 4 LIBERTY2  10 0     3
# 5   OLDOAK   8 1     8
# 6   OLDOAK   9 1     9
# 7   OLDOAK  10 1    10
# 8   OLDOAK  10 1    10

Answer 2

这是你想要的？

DS_F <- DS_F %>%
  mutate(FARM = as.factor(FARM),
         RULE = case_when(AGE == 10 ~ 3, 
                          AGE == 9 ~ 2,
                          AGE == 8 ~ 1))

产生

> DS_F %>%
+   mutate(FARM = as.factor(FARM),
+          RULE = case_when(AGE == 10 ~ 3, 
+                           AGE == 9 ~ 2,
+                           AGE == 8 ~ 1))
      FARM AGE Y RULE
1 LIBERTY2   8 0    1
2 LIBERTY2   9 0    2
3 LIBERTY2  10 0    3
4 LIBERTY2  10 0    3
5   OLDOAK   8 1    1
6   OLDOAK   9 1    2
7   OLDOAK  10 1    3
8   OLDOAK  10 1    3

具有以下数据类型

> str(DS_F)
'data.frame':   8 obs. of  4 variables:
 $ FARM: Factor w/ 2 levels "LIBERTY2","OLDOAK": 1 1 1 1 2 2 2 2
 $ AGE : num  8 9 10 10 8 9 10 10
 $ Y   : num  0 0 0 0 1 1 1 1
 $ RULE: num  1 2 3 3 1 2 3 3