在javascript中使用条件进行数组分组答案

【问题标题】：Array groupping with condition in javascript在javascript中使用条件进行数组分组
【发布时间】：2023-01-08 22:49:40
【问题描述】：

所以我有一系列来自 BE 的响应，其结构如下：

    const answer= [
  {
    "Tanggal": "2023-01-05",
    "Plant": "Ranc",
    "Gedung / Zona": "Zona 2",
    "Sektor": "9",
    "Line": "34",
    "Shift Running": "3",
    "SKU Number": "310902",
    "RPH Input": "Planned (H-1)"
  },
  {
    "Tanggal": "2023-01-05",
    "Plant": "Ranc",
    "Gedung / Zona": "Zona 2",
    "Sektor": "9",
    "Line": "34",
    "Shift Running": "2",
    "SKU Number": "310902",
    "RPH Input": "Revisi"
  },
  {
    "Tanggal": "2023-01-05",
    "Plant": "Ranc",
    "Gedung / Zona": "Zona 2",
    "Sektor": "9",
    "Line": "36",
    "Shift Running": "3",
    "SKU Number": "300360",
    "RPH Input": "Planned (H-1)"
  },
  {
    "Tanggal": "2023-01-05",
    "Plant": "Ranc",
    "Gedung / Zona": "Zona 2",
    "Sektor": "9",
    "Line": "36",
    "Shift Running": "3",
    "SKU Number": "310907",
    "RPH Input": "Planned (H-1)"
  },
  {
    "Tanggal": "2023-01-05",
    "Plant": "Ranc",
    "Gedung / Zona": "Zona 2",
    "Sektor": "9",
    "Line": "37",
    "Shift Running": "3",
    "SKU Number": "310908",
    "RPH Input": "Planned (H-1)"
  },
  {
    "Tanggal": "2023-01-05",
    "Plant": "Ranc",
    "Gedung / Zona": "Zona 2",
    "Sektor": "11",
    "Line": "43",
    "Shift Running": "1",
    "SKU Number": "310101",
    "RPH Input": "Planned (H-1)"
  },
  {
    "Tanggal": "2023-01-06",
    "Plant": "Ranc",
    "Gedung / Zona": "Zona 2",
    "Sektor": "11",
    "Line": "44",
    "Shift Running": "2",
    "SKU Number": "321294",
    "RPH Input": "Planned (H-1)"
  },
  {
    "Tanggal": "2023-01-06",
    "Plant": "Ranc",
    "Gedung / Zona": "Zona 2",
    "Sektor": "11",
    "Line": "44",
    "Shift Running": "3",
    "SKU Number": "300079",
    "RPH Input": "Revisi"
  }
];

如果“Tanggal”、“Plant”、“Gedung/Zona”、“sektor”、Line 和 SKU 编号相同（不包括班次编号）但 RPH 输入值为“Revisi”，我尝试将其分组为日期", 它只会对来自 RPH 输入的值进行分组，该值具有值 revisi 而不是 Planned (H-1)，预期数组是这样的，日期的值是 Shift Running 的累积值（这里是预期的大批）：

const tranfrdata=[{ "2023-01-05": 12,
  "2023-01-06": 5 }]

可以根据我上面提到的逻辑对其进行分组，是否可以这样做？或者有什么帮助吗？

【问题讨论】：

我很难理解这个问题。只是您要按日期添加 Shift Running，但不包括 Revisi 的 RPH Input？我们可以忽略其他字段吗？
嗯，不排除，假设我有两个条件，其中 tanggal、plant、gedung 等具有相同的值，但 RPH 输入有“Planned H-1”和“Revisi”，所以它只选择“Revisi”而不是“计划的 H-1”，以及按日期运行的加班。
啊，我想我现在明白了。
先生有什么帮助吗？ @本斯蒂芬斯
源数据中是否可以有两个具有相同 Tanggal、Plant、Gedung / Zona、Sektor、Line、SKU Number 和 RPH Input 的项目？

标签： javascript arrays object

【解决方案1】：

如果我正确理解你的问题，我认为最好的方法是将数组分隔为Planned (H-1)和Revisi，然后迭代第一个数组并使用SKU编号检查它是否存在于第二个数组中，如果不存在' 只从第一个数组累加，如果是，从第二个数组累加：

const answer= [
  {
    "Tanggal": "2023-01-05",
    "Plant": "Ranc",
    "Gedung / Zona": "Zona 2",
    "Sektor": "9",
    "Line": "34",
    "Shift Running": "3",
    "SKU Number": "310902",
    "RPH Input": "Planned (H-1)"
  },
  {
    "Tanggal": "2023-01-05",
    "Plant": "Ranc",
    "Gedung / Zona": "Zona 2",
    "Sektor": "9",
    "Line": "34",
    "Shift Running": "2",
    "SKU Number": "310902",
    "RPH Input": "Revisi"
  },
  {
    "Tanggal": "2023-01-05",
    "Plant": "Ranc",
    "Gedung / Zona": "Zona 2",
    "Sektor": "9",
    "Line": "36",
    "Shift Running": "3",
    "SKU Number": "300360",
    "RPH Input": "Planned (H-1)"
  },
  {
    "Tanggal": "2023-01-05",
    "Plant": "Ranc",
    "Gedung / Zona": "Zona 2",
    "Sektor": "9",
    "Line": "36",
    "Shift Running": "3",
    "SKU Number": "310907",
    "RPH Input": "Planned (H-1)"
  },
  {
    "Tanggal": "2023-01-05",
    "Plant": "Ranc",
    "Gedung / Zona": "Zona 2",
    "Sektor": "9",
    "Line": "37",
    "Shift Running": "3",
    "SKU Number": "310908",
    "RPH Input": "Planned (H-1)"
  },
  {
    "Tanggal": "2023-01-05",
    "Plant": "Ranc",
    "Gedung / Zona": "Zona 2",
    "Sektor": "11",
    "Line": "43",
    "Shift Running": "1",
    "SKU Number": "310101",
    "RPH Input": "Planned (H-1)"
  },
  {
    "Tanggal": "2023-01-06",
    "Plant": "Ranc",
    "Gedung / Zona": "Zona 2",
    "Sektor": "11",
    "Line": "43",
    "Shift Running": "2",
    "SKU Number": "321294",
    "RPH Input": "Planned (H-1)"
  },
  {
    "Tanggal": "2023-01-06",
    "Plant": "Ranc",
    "Gedung / Zona": "Zona 2",
    "Sektor": "11",
    "Line": "44",
    "Shift Running": "3",
    "SKU Number": "300079",
    "RPH Input": "Planned (H-1)"
  }
];

const planned = answer.filter(obj => obj["RPH Input"] === "Planned (H-1)")
const revisi = answer.filter(obj => obj["RPH Input"] === "Revisi")

const transferData = planned.reduce((acc, curr) => {
  const revisiObj = revisi.findLast(obj => obj["SKU Number"] === curr["SKU Number"])
  let finalObj = curr
  if (revisiObj) {
    finalObj = revisiObj
  }
  return {
    ...acc,
    [finalObj["Tanggal"]]: finalObj["Tanggal"] in acc ? acc[finalObj["Tanggal"]] + Number(finalObj["Shift Running"]) : Number(finalObj["Shift Running"])
  }
}, {})

console.log(transferData)

【讨论】：

兄弟出错了……“revisi.findLast 不是一个函数”
但答案已经是我所期望的..
@nabatiadmin 如果错误发生在你应用代码之后，那么很难从这里调试，你这边可能有一些不同的结构，也许尝试将 findLast 更改为 find 并查看它是否有效
它可以工作，但是当它出现不同的情况时，我认为它有一些问题......，先生，你介意看一下吗？ @达姆扎基
更新了问题...

【解决方案2】：

创建一个空对象 groupedData，它将存储分组数据。
循环遍历答案数组中的元素。
对于每个元素，检查 Tanggal、Plant、Gedung / Zona、 Sektor、Line、Shift Running 和 SKU Number 属性相同作为当前元素。如果是，并且 RPH 输入是“Revisi”，将 Shift Running 属性的值添加到 groupedData 相应日期的对象。如果 RPH 输入不是“Revisi”，跳过元素。

循环后，groupedData 对象将包含分组数据。然后您可以使用 Object.entries(groupedData) 将其转换为一组键值对，然后您可以进一步操作如所须。

const answer= [
  {
    "Tanggal": "2023-01-05",
    "Plant": "Ranc",
    "Gedung / Zona": "Zona 2",
    "Sektor": "9",
    "Line": "34",
    "Shift Running": "3",
    "SKU Number": "310902",
    "RPH Input": "Planned (H-1)"
  },
  {
    "Tanggal": "2023-01-05",
    "Plant": "Ranc",
    "Gedung / Zona": "Zona 2",
    "Sektor": "9",
    "Line": "34",
    "Shift Running": "2",
    "SKU Number": "310902",
    "RPH Input": "Revisi"
  },
  {
    "Tanggal": "2023-01-05",
    "Plant": "Ranc",
    "Gedung / Zona": "Zona 2",
    "Sektor": "9",
    "Line": "36",
    "Shift Running": "3",
    "SKU Number": "300360",
    "RPH Input": "Planned (H-1)"
  },
  {
    "Tanggal": "2023-01-05",
    "Plant": "Ranc",
    "Gedung / Zona": "Zona 2",
    "Sektor": "9",
    "Line": "36",
    "Shift Running": "3",
    "SKU Number": "310907",
    "RPH Input": "Planned (H-1)"
  },
  {
    "Tanggal": "2023-01-05",
    "Plant": "Ranc",
    "Gedung / Zona": "Zona 2",
    "Sektor": "9",
    "Line": "37",
    "Shift Running": "3",
    "SKU Number": "310908",
    "RPH Input": "Planned (H-1)"
  },
  {
    "Tanggal": "2023-01-05",
    "Plant": "Ranc",
    "Gedung / Zona": "Zona 2",
    "Sektor": "11",
    "Line": "43",
    "Shift Running": "1",
    "SKU Number": "310101",
    "RPH Input": "Planned (H-1)"
  },
  {
    "Tanggal": "2023-01-06",
    "Plant": "Ranc",
    "Gedung / Zona": "Zona 2",
    "Sektor": "11",
    "Line": "43",
    "Shift Running": "2",
    "SKU Number": "321294",
    "RPH Input": "Planned (H-1)"
  },
  {
    "Tanggal": "2023-01-06",
    "Plant": "Ranc",
    "Gedung / Zona": "Zona 2",
    "Sektor": "11",
    "Line": "44",
    "Shift Running": "3",
    "SKU Number": "300079",
    "RPH Input": "Planned (H-1)"
  }
]

const groupedData = {};

for (const element of answer) {
  if (element['RPH Input'] === 'Revisi') {
    if (
      element['Tanggal'] === element['Tanggal'] &&
      element['Plant'] === element['Plant'] &&
      element['Gedung / Zona'] === element['Gedung / Zona'] &&
      element['Sektor'] === element['Sektor'] &&
      element['Line'] === element['Line'] &&
      element['Shift Running'] === element['Shift Running'] &&
      element['SKU Number'] === element['SKU Number']
    ) {
      if (!groupedData[element['Tanggal']]) {
        groupedData[element['Tanggal']] = 0;
      }
      groupedData[element['Tanggal']] += element['Shift Running'];
    }
  }
}

const tranfrdata = Object.entries(groupedData);
console.log(groupedData);

【讨论】：