SQL 查询以选择具有包含在数组中的值的所有行答案

【问题标题】：SQL query to select all rows with a value included in an arraySQL 查询以选择具有包含在数组中的值的所有行
【发布时间】：2023-01-02 03:51:59
【问题描述】：

我有一个数组 projectIds 和 ids。我想从数据库中选择数组中存在的值为 project_id 的所有行：

const { sequelize } = require("./db");  //The db and sequelize work correctly in other places, so can be assumed to be set up correctly.
const { QueryTypes } = require("sequelize");

const projectIds = [1,2,3,4];

let rows = await sequelize.query(
    "SELECT * FROM `table_name` WHERE project_id IN = ?",
    {
        replacements: [`${projectIds}`],
        type: QueryTypes.SELECT,
    }
);

查询返回UnhandledPromiseRejectionWarning: Error。这段代码有什么问题？

【问题讨论】：

${projectIds} 计算结果为 '1,2,3,4' 没有括号。如果安全的话，也许你可以直接在 SQL 中编写数组 WHERE project_id IN [1,2,3,4]
谢谢，我试了一下，还是报错。

标签： sql node.js sequelize.js

【解决方案1】：

试试这个：

const { sequelize } = require("./db");  //The db and sequelize work correctly in other places, so can be assumed to be set up correctly.
const { QueryTypes } = require("sequelize");

const projectIds = [1,2,3,4];

let rows = await sequelize.query(
    'SELECT * FROM `
"table_name" WHERE project_id IN = (:projectIds)',
    {
        replacements: projectIds,
        type: QueryTypes.SELECT,
    }
);

【讨论】：