【发布时间】:2022-12-27 23:59:54
【问题描述】:
I have tried this but gives me a promise I just want do it like this.
function doSome() {
return new Promise(
function(res, rej) {
let d = [];
for (var i = 0; i < 100; i++) {
d.push(i)
}
res(d)
})
}
console.log(doSome().then((val)=>{return val}));
【问题讨论】:
标签: javascript promise