【发布时间】：2022-12-04 11:14:25
【问题描述】：
I have a table similar to below
| id | phone | email | dob |
| -- | ---------- | ---- | ---- |
| 1 | 04-------61 | example@gmail.com| 196949200 |
| 2 | 04-------61 | example@gmail.com| 296949200 |
| 3 | 55-------51 | example@gmail.com| 396949200 |
| 4 | 04-------61 | test@gmail.com | 496949200 |
| 5 | 66-------61 | test@gmail.com | 596949200 |
| 6 | 77-------61 | another@gmail.com| 696949200 |
I want to get rows that have a distinct \'phone\' and \'email\' (not a distinct combination) along with the data associated with the first instance (here dob as an example).
My desired output:
| id | phone | email | dob |
| -- | ---------- | ---- | ---- |
| 1 | 04-------61 | example@gmail.com| 196949200 |
| 5 | 66-------61 | test@gmail.com | 596949200 |
| 6 | 77-------61 | another@gmail.com| 696949200 |
Is there a way I can achieve this? I\'ve tried using distinct and group by but I can\'t see how they would be helpful in this case.
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Please provide DDL + DML commands
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If distinct on phone and email, your result for phone = 04-----61 will definitely be 2 rows, one is for example@gmail.com, another is test@gmail.com