如何使用 lookup 或 hashmap 而不是 if else？

Question

if Profit<=10000:
    print('Profit Rating is 1')
elif 10001<=Profit<=20000:
    print('Profit Rating is 2')
elif 20001<=Profit<=30000:
    print('Profit Rating is 3')
elif 30001<=Profit<=40000:
    print('Profit Rating is 4')
elif 40001<=Profit<=50000:
    print('Profit Rating is 5')
elif 50001<=Profit<=60000:
    print('Profit Rating is 6')
elif 60001<=Profit<=70000:
    print('Profit Rating is 7')
elif 70001<=Profit<=80000:
    print('Profit Rating is 8')
elif 80001<=Profit<=90000:
    print('Profit Rating is 9')
else:
    print('Profit Rating is 10')

如果还有，请帮我删除上面的内容。 我尝试使用查找和映射，但它不起作用。

我想摆脱 if、elif 和 else。

Answer 1

使用简单的数学：

import math

if Profit > 90000:
    profit_rating = 10
else:
    profit_rating = math.ceil(Profit / 10000)

print(f"Profit Rating is {profit_rating}")

它会将您的数字除以 10,000，然后四舍五入。这基本上就是您在原始 if/else 解决方案中尝试（手动）执行的操作。