如何将数字添加到变量？

Question

所以，我一直在尝试构建一个 python 数字猜谜游戏。我是新手，我不知道如何将 +1 添加到我的机会变量中。我已经像这里一样尝试过 +=1 但无论如何它总是显示 1 作为输出。

import random

numbers = 1,2,3,4,5,6,7,8,9,10 
user = None
hidden = random.choice(numbers)

print("Welcome to volty's's number guessing game!")
def game():
  chance = 0
  user = int(input("choose a number from 1 to 10: "))
  if user > hidden:
    print ("ur number is more than the hidden number")
    game()
    chance += 1
  elif user < hidden: 
   print ("ur number is less than the hudden number")
   game()
   chance = +1
  elif user == hidden:
    print (" u guessed the hidden number!")
    print ("the hidden number was:",hidden)
    print (f"u guessed it in {chance +1} step {'s' if chance > 1 else ' '}")
  
game()

这就是代码。

Answer 1

这里的大问题是您使用递归的方式。答案很简单： 在递归之前更改变量

import random

numbers = 1, 2, 3, 4, 5, 6, 7, 8, 9, 10
user = None
hidden = random.choice(numbers)

print("Welcome to volty's's number guessing game!")


def game(chance):
    user = int(input("choose a number from 1 to 10: "))
    if user > hidden:
        print("ur number is more than the hidden number")
        chance += 1
        game(chance)
    elif user < hidden:
        print("ur number is less than the hudden number")
        chance += 1
        game(chance)
    elif user == hidden:
        print(" u guessed the hidden number!")
        print("the hidden number was:", hidden)
        print(f"u guessed it in {chance + 1} step {'s' if chance > 1 else ' '}")


game(0)

查看有关递归的教程

Answer 2

这与 Noah 的回答非常相似，但您也可以在递归调用该函数时直接增加机会：

import random

numbers = 1, 2, 3, 4, 5, 6, 7, 8, 9, 10
user = None
hidden = random.choice(numbers)
print(hidden)

print("Welcome to volty's's number guessing game!")

chance = 0

def game(chance):
    user = int(input("choose a number from 1 to 10: "))
    if user > hidden:
        print("ur number is more than the hidden number")
        game(chance + 1)
        # chance += 1
    elif user < hidden:
        print("ur number is less than the hudden number")
        game(chance + 1)
        # chance += 1
    elif user == hidden:
        print(" u guessed the hidden number!")
        print("the hidden number was:", hidden)
        print(f"u guessed it in {chance + 1} step{'s' if chance > 1 else ' '}")


game(chance)

Answer 3

这是因为您不必在每次失败时都重新调用函数“game()”。 理想情况下，您应该创建条件“is_hidden_​​found”，只有当玩家成功找到号码时该条件才为真。 因此，在获胜和“机会”增加之前使用相同的变量。

import random

print("Welcome to volty's's number guessing game!")
def game():
  numbers = 1,2,3,4,5,6,7,8,9,10 
  user = None
  hidden = random.choice(numbers) # maybe use random.randint(0, 10)

  is_hidden_found = False
  chance = 0
  while is_hidden_found == False:

    user = int(input("choose a number from 1 to 10: "))
    if user > hidden:
      print ("ur number is more than the hidden number")
      chance += 1
    elif user < hidden: 
     print ("ur number is less than the hudden number")
     chance += 1
    elif user == hidden:
      is_hidden_found = True
      print (" u guessed the hidden number!")
      print ("the hidden number was:",hidden)
      print (f"u guessed it in {chance +1} step {'s' if chance > 1 else ' '}")

game()

在学习的同时玩得开心；）

Answer 4

你可以像下面这样尝试

import random

numbers = 1,2,3,4,5,6,7,8,9,10 
hidden = random.choice(numbers)

print("Welcome to volty's's number guessing game!")

def game(chance):
  user = int(input("choose a number from 1 to 10: "))
  if user > hidden:
    print ("ur number is more than the hidden number")
    game(chance)
    chance += 1
  elif user < hidden: 
   print ("ur number is less than the hudden number")
   game(chance)
   chance = +1
  elif user == hidden:
    print (" u guessed the hidden number!")
    print ("the hidden number was:",hidden)
    print (f"u guessed it in {chance +1} step {'s' if chance > 1 else ' '}")
  

game(chance=0)

Answer 5

解决方案：将您“chance = 0”移到函数范围之外开始。

原因：每次您的代码进入 if 语句时，它都会将机会值重新初始化为 0。