【发布时间】:2022-11-18 04:44:47
【问题描述】:
我正在从我的数据库中获取数据,这就是我得到的:
Array
(
[0] => Array
(
[username] => example@gmail.com
[processedDate] => 2022-11-09 10:22:00
[processed] => 1
)
[1] => Array
(
[username] => example@gmail.com
[processedDate] => 0000-00-00 00:00:00
[processed] => 0
)
[2] => Array
(
[username] => example@gmail.com
[processedDate] => 2022-10-26 11:07:00
[processed] => 1
)
[3] => Array
(
[username] => example@gmail.com
[processedDate] => 2022-11-14 17:21:00
[processed] => 1
)
[4] => Array
(
[username] => example@gmail.com
[processedDate] => 2022-09-19 10:50:00
[processed] => 1
)
)
很酷,但是我需要访问 username 属性,这与我使用对象 ($myArray->username) 时类似。
我试过这个但它不起作用,因为它不是一个对象,它是一个数组。
foreach($arr as $var) {
foreach($var as $el) {
echo $el->username;
}
}
我也试过这个:
foreach($arr as $var) {
echo $var['username'];
}
我的目标是访问 username、processedDate 和 processes 属性以使用它们并评估条件。
我想得到这个:
Array
(
[0] => Array
(
[username] => example@gmail.com
)
[1] => Array
(
[username] => example@gmail.com
)
[2] => Array
(
[username] => example@gmail.com
)
[3] => Array
(
[username] => example@gmail.com
)
[4] => Array
(
[username] => example@gmail.com
)
)
这是我的完整代码:
$sql = "SELECT username, processedDate, processed FROM users_test";
$stmt = $conn->prepare($sql);
$stmt->execute();
$result = $stmt->get_result();
while ($row = $result->fetch_assoc()){
$arr[] = $row;
}
echo "<pre>";
print_r($arr); // The result of this is the first code I posted here.
【问题讨论】: