在 mb 单独列中获取文件夹及其文件的相对路径？

Question

我需要在单独的 csv 列中找到文件夹及其长度为 MB 的文件的相对路径，并将该 csv 文件与另一个 csv 文件进行比较，并在绝对路径中的另一个 csv 中打印长度不匹配的文件路径

$srcpth = "C:\Users\vavenkatamanoj\Downloads"
$files = Get-ChildItem -Path $srcpth -File -Recurse

foreach ($f in $files)
{
    $filen = $f.Name
    $relativePath = $f.fullname.remove(0,($srcpth.length))
    $filesize = $f.Length
    Write-Output "$relativePath,$filesize" | Out-File C:\Users\vavenkatamanoj\Downloads\check.csv -Append
}

我尝试使用此脚本来获取具有大小的相对路径。没问题，但文件路径和长度在同一列中返回；我需要单独的列。谁能帮我？

Answer 1

$srcpth = "C:UsersavenkatamanojDownloads" 
$files = Get-ChildItem -Path $srcpth -File -Recurse 
$result = foreach ($f in $files) {

[pscustomobject][ordered]@{
        fileName = $f.Name
        RelativePath  =  $f.fullname.remove(0,($srcpth.length))
        FileSize = $f.Length
    }



}
$result | Export-Csv "c:	empoutput.csv" -NoTypeInformation -Append

使用 PSCustomObject 创建结构化数据。请找到以下链接以获取更多信息： https://learn.microsoft.com/en-us/powershell/scripting/learn/deep-dives/everything-about-pscustomobject?view=powershell-7.3

Answer 2

继续我的评论，

为什么不创建一个包含长度、绝对路径和相对路径的 CSV 文件？

$srcpth = 'C:UsersavenkatamanojDownloads'

# needed for Resolve-Path -Relative
$currentPath = (Get-Location).Path
Set-Location $srcpth
# you could now remove the -Path $srcpth if you like
$result = Get-ChildItem -Path $srcpth -File -Recurse | ForEach-Object {
    # output Objects
    [PsCustomObject]@{
        FileName     = $_.Name
        FileSize     = $_.Length
        RelativePath = $_.FullName | Resolve-Path -Relative
        AbsolutePath = $_.FullName
    }
}

# now, output the data as CSV
$result | Export-Csv -Path 'C:UsersavenkatamanojDownloadscheck.csv' -NoTypeInformation
# restore the current location
Set-Location $currentPath