UPSERT 包括从另一个表中选择数据列表

Question

我有一组很长的数据，如果数据存在或不存在，应该插入（或更新）这些数据。

我走了这么远，但不知道我是否走在正确的轨道上。也许一些 MySQL 专家知道如何完成该语句或更正它。

我有两张桌子：

领域

id	number	name
1	4578	FirstArea
2	4328	SomeArea
3	3214	SecondArea

顾客

id	first_name	last_name	identifier	area_id
1	James	Jameson	HJ238	1
2	Pepper	Potts	NULL	NULL
3	Peter	Parker	NULL	2
4	Anis	Abraham	NULL	NULL
5	Karl	Klux	HI438	NULL

我想用客户数据插入或更新表Customers。到目前为止，我已经做到了：

set @last_name="James", @first_name="Jameson", @identifier="HZ732732", @cc="FirstArea";
set @last_name="Abraham", @first_name="Anis", @identifier="JI72373", @cc="SecondArea;
set @last_name="Potts", @first_name="Pepper", @identifier="KI83282", @cc="SomeArea;

set @id = (SELECT id from Customers c WHERE c.first_name = @first_name AND e.last_name = @last_name;);
set @cc_id = (SELECT id FROM Areas a WHERE aa.number = @cc;);
INSERT INTO Customers c (id, first_name, last_name, identifier, area_id) values (@id, @first_name, @last_name, @identifier, @cc_id)
ON DUPLICATE key UPDATE e.identifier = @identifier, e.area_id = @cc_id;

在这里提琴：http://www.sqlfiddle.com/#!9/cb988e

对于循环部分，我不知道，如果这与变量一起工作，我不确定。

我不仅有三个条目，而且大约有 3 个条目。要插入 450 个条目。

Answer 1

调查：

CREATE TABLE Customers(
  id int unsigned NOT NULL AUTO_INCREMENT,  -- added
  first_name VARCHAR(55),
  last_name VARCHAR(55),
  identifier VARCHAR(55),
  area_id int unsigned,
  PRIMARY KEY (id),
  KEY area_id (area_id)
);

CREATE TABLE Areas(
  id int unsigned NOT NULL,
  number VARCHAR(55),
  area_name VARCHAR(55),
  PRIMARY KEY (id)
);

INSERT INTO Customers VALUES
(1, 'James', 'Jameson', 'HJ238', 1),
(2, 'Pepper', 'Potts',NULL, NULL),
(3, 'Peter', 'Parker', NULL, 2),
(4, 'Anis', 'Abraham',NULL, NULL),
(5, 'Karl', 'Klux','HI438', NULL);
SELECT * FROM Customers;

INSERT INTO Areas VALUES
(1, '4578', 'FirstArea'),
(2, '4328', 'SomeArea'),
(3, '3214', 'SecondArea');
SELECT * FROM Areas;

Records: 5  Duplicates: 0  Warnings: 0

id	first_name	last_name	identifier	area_id
1	James	Jameson	HJ238	1
2	Pepper	Potts	null	null
3	Peter	Parker	null	2
4	Anis	Abraham	null	null
5	Karl	Klux	HI438	null

Records: 3  Duplicates: 0  Warnings: 0

id	number	area_name
1	4578	FirstArea
2	4328	SomeArea
3	3214	SecondArea

-- the value (a row from the file) was loaded by some way
-- assigning it to the variable
SET @sql := 'set @last_name="James", @first_name="Jameson", @identifier="HZ732732", @cc="FirstArea";';

-- and execute
PREPARE stmt FROM @sql;
EXECUTE stmt;
DROP PREPARE stmt;

SELECT @last_name, @first_name, @identifier, @cc; -- check the result

Statement prepared

@last_name	@first_name	@identifier	@cc
James	Jameson	HZ732732	FirstArea

set @id = (SELECT id from Customers c WHERE c.first_name = @first_name AND c.last_name = @last_name);
set @cc_id = (SELECT id FROM Areas a WHERE a.number = @cc);

SELECT @id, @cc_id; -- print for debugging purposes

INSERT INTO Customers (id, first_name, last_name, identifier, area_id) 
values (@id, @first_name, @last_name, @identifier, @cc_id)
ON DUPLICATE key UPDATE identifier = @identifier, area_id = @cc_id;

@id	@cc_id
null	null

SELECT * FROM Customers;

id	first_name	last_name	identifier	area_id
1	James	Jameson	HJ238	1
2	Pepper	Potts	null	null
3	Peter	Parker	null	2
4	Anis	Abraham	null	null
5	Karl	Klux	HI438	null
6	Jameson	James	HZ732732	null

-- next lines to be prepared/executed with further queries pack execution
SET @sql := 'set @last_name="Abraham", @first_name="Anis", @identifier="JI72373", @cc="SecondArea";';
SET @sql := 'set @last_name="Potts", @first_name="Pepper", @identifier="KI83282", @cc="SomeArea";';

fiddle

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PS。修复了许多小错误和错误 - 与您的代码逐个字符进行比较。