在日期列表中搜索并找到下一个最近的未来日期

Question

问题：

给定一个支付周期和销售日期的列表。对于每个销售日期，确定下一个发薪日。

Pay periods (given)	Sale date (given)	Pay day (To be generated)
June 4	June 4	June 4
June 17	June 4	June 4
June 30	June 4	June 4
July 15	June 5	June 17
	June 5	June 17
	June 12	June 17
	June 16	June 17
	June 18	June 30
	June 22	June 30
	June 24	June 30
	June 28	June 30
	June 30	June 30
	July 1	July 15
	July 7	July 15
	July 8	July 15
	July 9	July 15
	July 10	July 15

Google Sheets: Yellow = given data, Blue = answer to be generated

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我得到的最近的：

=arrayformula(过滤器($A$2:$A,abs($A$2:$A-B2)=min(abs($A$2:$A-B2))))

这个公式是不正确的，因为对于某些销售日期，发薪日更早。销售日期必须始终在发薪日之前，因为在现实生活中，您只有在完成销售后才能获得报酬，而不是之前。

Answer 1

尝试：

=BYROW(B2:B, LAMBDA(x, SINGLE(FILTER(A2:A, A2:A>=x))))

或从另一个选项卡：

=BYROW(B2:B, LAMBDA(x, SINGLE(FILTER('New tab'!A2:A, 'New tab'!A2:A>=x))))

Answer 2

如果“付款日期”按升序排列，您可以尝试以下公式：

G2 = arrayformula(INDEX($A$2:$A$5,MATCH(MIN(ABS($A$2:$A$5-B2)),ABS($A$2:$A$5-B2),0)))

H2 = index($A$2:$A$5,match($G2,$A$2:$A$5)+1)

I2 = if(G2<B2,H2,G2)

然后：

F2 = if(arrayformula(INDEX($A$2:$A$5,MATCH(MIN(ABS($A$2:$A$5-B2)),ABS($A$2:$A$5-B2),0)))<B2,index($A$2:$A$5,match(arrayformula(INDEX($A$2:$A$5,MATCH(MIN(ABS($A$2:$A$5-B2)),ABS($A$2:$A$5-B2),0))),$A$2:$A$5)+1),arrayformula(INDEX($A$2:$A$5,MATCH(MIN(ABS($A$2:$A$5-B2)),ABS($A$2:$A$5-B2),0))))

希望它会有所帮助。

Answer 3

我是 SQL 的粉丝，所以这里有一个使用 QUERY() 的直观解决方案：

=BYROW(B2:B, LAMBDA(x, 
    QUERY(
        A:A, "
        SELECT 
            A 
        WHERE 
            A >= DATE '"&TEXT(x, "yyyy-mm-dd")&"' 
        ORDER BY 
            A 
        LIMIT 
            1 
        LABEL 
            A ''
        "
        , 1)
    ))

我把它扔进了你的谷歌表格，这样你就可以看到它的实际效果了！

编辑：我将它包裹在BYROW() 中，因此如果需要，您可以在一个单元格中使用它。