为什么不调用继承类的析构函数？ [复制]

Question

为什么不调用Circle析构函数？

#include "stdafx.h"
#include <iostream>

class Shape { 
public:
    Shape() { 
        std::cout << "Shape Constructor\n"; 
    };
    ~Shape() { 
        std::cout << "Shape Destructor\n"; 
    };
};

class Circle: public Shape {
public:
    Circle() { 
        std::cout << "Circle Constructor\n"; 
    };
    ~Circle() { 
        std::cout << "Circle Destructor\n"; 
    };
};

int _tmain(int argc, _TCHAR* argv[])
{
    Shape *object;  
    object = new Circle(); 
    delete object;
    return 0;
}

输出：

Shape Constructor
Circle Constructor
Shape Destructor

Answer 1

默认情况下，继承不允许派生类析构函数自动调用基类的析构函数。但是将基类的析构函数定义为virtual 可以使派生类在销毁之前隐式调用基类的析构函数。