在两个参数之间查找多个字符串答案

【问题标题】：Find multiple strings between two arguments在两个参数之间查找多个字符串
【发布时间】：2022-10-13 20:29:09
【问题描述】：

我正在尝试创建一个函数，它将在两个参数之间获取一个字符串（改写和重定向）。我无法绕过它。

我有一个看起来像这样的字符串：

add_header X-Robots-Tag "noindex, follow" always; rewrite ^/en/about/Administration/index.aspx /en/about/more-about/administration redirect; rewrite ^/en/about/Administration/supervisory-board/index.aspx /nl/over/meer-over/administration redirect; rewrite ^/en/about/Departments-sections-and-fields/index.aspx /en/about/more-about/department-divisions-and-fields redirect; rewrite ^/en/about/For-companies/index.aspx /en/about/more-about/for-companies redirect; rewrite ^/en/about/contact-information/index.aspx /en/about/more-about/contact-information redirect; rewrite ^/en/about/index.aspx /nl/over redirect;

我想要以下输出：

/en/about/Administration/index.aspx /en/about/more-about/administration
 
/en/about/Administration/supervisory-board/index.aspx /nl/over/meer-over/administration 

/en/about/Departments-sections-and-fields/index.aspx /en/about/more-about/department-divisions-and-fields  

/en/about/For-companies/index.aspx /en/about/more-about/for-companies

/en/about/contact-information/index.aspx /en/about/more-about/contact-information

/en/about/index.aspx /nl/over

获取两个参数之间的所有字符串的正确正则表达式或方法是什么？

【问题讨论】：

标签： go kubernetes

【解决方案1】：

尝试：

rewrite ^(.*?)s+redirect;

在线查看demo

rewrite ^ - 字面意思是“重写”左侧的单词边界和右侧的空格后跟文字“^”；
(.*?) - 匹配（惰性）0+ 个字符；
s+redirect; - 字面意思是在左侧 1+ 个空白字符和右侧分号之间“重定向”。

请参阅在线 GO demo，它将打印：

/en/about/Administration/index.aspx /en/about/more-about/administration
/en/about/Administration/supervisory-board/index.aspx /nl/over/meer-over/administration
/en/about/Departments-sections-and-fields/index.aspx /en/about/more-about/department-divisions-and-fields
/en/about/For-companies/index.aspx /en/about/more-about/for-companies
/en/about/contact-information/index.aspx /en/about/more-about/contact-information
/en/about/index.aspx /nl/over

【讨论】：