Java：询问用户是否想再玩一次？ [关闭]

Question

我正在制作一个石头剪刀布游戏，一旦计算机或用户有一个最好的 2/3，那么它应该提示他们是否想再次玩游戏。如果“是”则程序重新启动，如果“否”则 system.exit 我猜。

我该怎么办？

    public static void main(String[] args) {
    Random r = new Random();
    int gameCount = 0;
    int computerWins = 0;
    int playerWins = 0;
    int rock, paper, scissors;
    rock = 1;
    paper = 2;
    scissors = 3;
    int playerChoice = 0;
    int computerChoice;

    System.out.println("Welcome to Rock Paper Scissors! Best 2 out of 3!");

    //While the game count is less than 3, the loop will repeat
    while (gameCount < 3) {
        computerChoice = r.nextInt(3) + 1;
        System.out.println("Enter \"Rock\", \"Paper\", or \"Scissors\"");
        String USER_Input = userInput.next();
        if (USER_Input.equalsIgnoreCase("Rock")) {
            playerChoice = 1;
        }
        if (USER_Input.equalsIgnoreCase("Paper")) {
            playerChoice = 2;
        }
        if (USER_Input.equalsIgnoreCase("Scissors")) {
            playerChoice = 3;
        }
        //If player enters anything besides rock, paper, or scissors
        if (playerChoice <= 0 || playerChoice > 3) {
            System.out.println("That wasn't an option");
            computerWins++;
            gameCount++;
            System.out.println("Not a valid input! Computer Wins!\n" +
                    "Player has won " +playerWins + " times and the computer " +
                    "has won " + computerWins + " times");

            //The game goes on, and the winners are added up!
        } else if (playerChoice == 1 && computerChoice == 2) {
            computerWins++;
            gameCount++;
            System.out.println("Rock v Paper! Computer Wins!\n" +
                    "Player has won " + playerWins + " times and the computer " +
                    "has won " + computerWins + " times");
        } else if (playerChoice == 2 && computerChoice == 1) {
            playerWins++;
            gameCount++;
            System.out.println("Paper v Rock! Player Wins!\n" +
                    "Player has won " + playerWins + " times and the computer " +
                    "has won " + computerWins + " times");
        } else if (playerChoice == 2 && computerChoice == 3) {
            computerWins++;
            gameCount++;
            System.out.println("Paper v Scissors! Computer Wins!\n" +
                    "Player has won " + playerWins + " times and the computer " +
                    "has won " + computerWins + " times");
        } else if (playerChoice == 3 && computerChoice == 2) {
            playerWins++;
            gameCount++;
            System.out.println("Scissors v Paper! Player Wins!\n" +
                    "Player has won " + playerWins + " times and the computer " +
                    "has won " + computerWins + " times");
        } else if (playerChoice == 3 && computerChoice == 1) {
            computerWins++;
            gameCount++;
            System.out.println("Scissors v Rock! Computer Wins!\n" +
                    "Player has won " + playerWins + " times and the computer " +
                    "has won " + computerWins + " times");
        } else if (playerChoice == 1 && computerChoice == 3) {
            playerWins++;
            gameCount++;
            System.out.println("Rock v Scissors! Player Wins!\n" +
                    "Player has won " + playerWins + " times and the computer " +
                    "has won " + computerWins + " times");
        } else if (playerChoice == 1 && computerChoice == 1) {
            gameCount++;
            System.out.println("Rock v Rock! Tie!\n" +
                    "Player has won " + playerWins + " times and the computer " +
                    "has won " + computerWins + " times");
        } else if (playerChoice == 2 && computerChoice == 2) {
            gameCount++;
            System.out.println("Paper v Paper! Tie!\n" +
                    "Player has won " + playerWins + " times and the computer " +
                    "has won " + computerWins + " times");
        } else if (playerChoice == 3 && computerChoice == 3) {
            gameCount++;
            System.out.println("Paper v Paper! Tie!\n" +
                    "Player has won " + playerWins + " times and the computer " +
                    "has won " + computerWins + " times");
        }

        //Check if game count reaches max games then chooses a winner
        if (gameCount == 3 && computerWins > playerWins || computerWins == 2) {
            System.out.println("The Computer Wins!");
            break;
        } else if (gameCount == 3 && computerWins < playerWins || playerWins ==2) {
            System.out.println("The Player Wins!");
        } else if (gameCount == 3 && computerWins == playerWins) {
            System.out.println("The game is a tie!");
        }
    }
}

Answer 1

您的整个逻辑都在 main() 方法中。我建议您将 while{} 部分移到 play() 之类的新方法中。

在您的 main() 中实现一个新的 while() 提示您的消息并从键盘读取输入：

public static void main(String args[]) {
        Scanner inputScanner = new Scanner(System.in);
        String userInput = "";
        do {
            play();
            System.out.print("Do you want to play again ([Y] / n)? ");
            userInput = inputScanner.nextLine();
            System.out.println(userInput);
        } while (userInput.equals("Y") || userInput.equals(""));
}

高温超导

Answer 2

一种可能的解决方案是将游戏放在另一个 while 循环中（包含 gameCount 的循环），并在 while 循环中为变量创建一个 switch 语句，比如说gameContinue。在游戏结束时，用户会收到一个提示，说明是否继续。根据他们的回答，您可以更改变量 gameContinue 的值，然后就可以了。