我有一个问题，我无法按类别获取产品详细信息答案

【问题标题】：I have a problem that I could not fetch product details by category我有一个问题，我无法按类别获取产品详细信息
【发布时间】：2022-10-02 22:30:01
【问题描述】：

我有一个问题，我无法按类别获取产品详细信息因为 Views 包含两个变量，我无法让它们显示产品详细信息

模型

from django.db import models

# Create your models here.

class Category(models.Model):
    name = models.CharField(max_length=200)
    slug = models.CharField(max_length=200)


def __str__(self):
    return self.name

class Product(models.Model):
    Category = models.ForeignKey(Category, on_delete=models.CASCADE)
    name = models.CharField(max_length=200, null=False, blank=False)
    slug = models.CharField(max_length=200, null=False, blank=False)
    description = models.TextField(max_length=350, null=False, blank=False)
    image = models.ImageField( null=False, blank=False)
    quantity = models.IntegerField(null=False, blank=False)


def __str__(self):
    return self.name

网址

path(\'category/<str:product_category_slug>/<str:product_slug>/\', views.product_detail, name=\"product-detail\")

维维斯

def product_detail(request, product_category_slug=None, product_slug=None):
    #How do I get product details through this path that contains a category and then the product

我希望有一个人可以帮助我

标签： django django-views

【解决方案1】：

def product_detail(request, product_category_slug, product_slug):
    product = Product.objects.get(slug=product_slug, Category__slug=product_category_slug)
    if product:
       return product
    else: 
       return "Product not found"

我希望这将返回带有类别的项目对象。要获取类别详细信息，假设您想要获取类别名称及其 slug，您可以执行以下操作：类别名称为product.Category.name，slug 为product.Category.slug

【讨论】：

【解决方案2】：

你可以这样做

def get_product_details(request, category_slug, slug):
    # Change <Category> field name to <category> 
    product = get_object_or_404(Product, category__slug=category_slug, slug=slug)
    context = dict(product=product)
    return response(response, "product_detail.html", context)

或者这样：

def get_product_details(request, category_slug, slug):
     try:
          product = Product._default_manager.get(category__slug=category_slug, slug=slug)
     except Product.DoesNotExist:
          product = None
    context = dict(product=product)
    template_name = "product_404_template.html" if product is None else "product_detail.html"
    return response(response, template_name, context)

对于这两种情况，您仍然需要处理 404。

【讨论】：