在swift5中解压下载的文件答案

【问题标题】：Unzip a downloaded file in swift5在swift5中解压下载的文件
【发布时间】：2022-09-30 19:23:57
【问题描述】：

纽布在这里。我想快速解压缩 .tar.gz 文件。我知道如何解压缩一个扩展名的文件。现在请告诉我如何解压缩这个文件。我是否需要执行两次解压缩或 swift 中有任何其他选项？

提前致谢！！

 AF.download(ref)
            .downloadProgress(queue: progressQueue) { progress in
            }
            .responseData { response in
                if let data = response.value {
   
                }
            }```

标签： ios file unzip

【解决方案1】：

让组 = DispatchGroup()

    let folder = try! FileManager.default
        .url(for: .cachesDirectory, in: .userDomainMask, appropriateFor: nil, create: true)
        .appendingPathComponent("SourceFiles")
    for (indexVal, ref) in arrayURL.enumerated() {
        
        let destination: DownloadRequest.Destination = { _, _ in
                let fileURL = folder.appendingPathComponent(ref.lastPathComponent)
                return (fileURL, [.createIntermediateDirectories])
            }
      print(destination)
        
        group.enter()
                    let progressQueue = DispatchQueue(label: "com.alamofire.progressQueue", qos: .utility)
        AF.download(ref, to: destination).downloadProgress(queue: progressQueue) { progress in
                               print("Download Progress: \(progress.fractionCompleted)")
            
            DispatchQueue.main.async {
                guard let cell = self.tableProgress.cellForRow(at: NSIndexPath.init(row: indexVal, section: 0) as IndexPath) as? ProgressCell else {
                    return // or fatalError() or whatever
                }
                cell.progressView.progress = Float(progress.fractionCompleted)
            }
        }.response { responseData in
               switch responseData.result {
               case .success(let url):
                   guard let url = url else { return }
                   print("fileurl", url)
                   do {
                       let unzipDirectory = try Zip.quickUnzipFile(url)
                       print("unzipDirectory", unzipDirectory)
                       
                   }
                   catch{
                       
                   }
                   group.leave()

// self.urlLoad.append(url) case .failure(let error): print(error) } } } group.notify(queue: .main, execute: { // executed after all async calls in for loop finish print("done with all async calls") }) }

【讨论】：