如何用参数替换 %<string>答案

【问题标题】：How do I replace %<string> with the parameters如何用参数替换 %<string>
【发布时间】：2022-09-23 15:44:41
【问题描述】：

我收到这样的 API 响应。

{
  \"message\": \"The password needs at least %1 characters. Password should be having %param2 special characters in it. Create a new password and try again.\",
  \"parameters\": [
    \"8\",
    \"param2test\"
  ]
}

在这里，我应该搜索响应中是否有 %[string]，如果有，我需要将 %1 替换为参数的第一个数组元素，将 %2 替换为第二个，依此类推。可能有 n 个参数。我如何在 React 中做到这一点？

标签： javascript

【解决方案1】：

const r = {
    "message": "The password needs at least %1 characters. Password should be having %2 special characters in it. Create a new password and try again.",
    "parameters": [
        "8",
        "2"
    ]
}

const parameterizedString = (...args) => {
    const [str, ...params] = args;
    return str.replace(/%\d+/g, matchedStr => {
        const variableIndex = matchedStr.replace("%", "") - 1;
        return params[variableIndex];
    });
}
console.log(parameterizedString(r.message, ...r.parameters))

【讨论】：

我已经更新了问题，请检查您是否可以回答@reifocs

【解决方案2】：

const obj = {
  "message": "The password needs at least %1 characters. Password should be having %2 special characters in it. Create a new password and try again.",
  "parameters": [
    "8",
    "2"
  ]
};


function change({ message, parameters }) {
  let str = message;

  message.match(/(%[0-9]+)/g).forEach((item, i) => {
    str = str.replace(item, parameters[i]);
  })

  return str;
}

console.log(change(obj));

【讨论】：

这个问题是假设我在字符串中有 %1 %2 %100 它仍然匹配数组的第三个元素
它应该是这样的，是不是应该对消息中的任意数量的%[number] 执行此操作。

【解决方案3】：

你可以试试这个：

const obj = {
  "message": "The password needs at least %1 characters. Password should be having %2 special characters in it. Create a new password and try again.",
  "parameters": [
    "8",
    "2"
  ]
}

const regex = /%\d/g;
function f(match){
  const m = Number(match.slice(1))
  return obj.parameters[m-1]
}

【讨论】：