如何在 mongodb 的 django 模型中建立一对一关系？

Answer 1

如果你使用 djongo，你可以创建 EmbeddedField 类：

class EmbeddedField(MongoField):
    def __init__(
        self,
        model_container: typing.Type[Model],
        model_form_class: typing.Type[forms.ModelForm] = None,
        model_form_kwargs: dict = None,
        *args, 
        **kwargs
   ):

之后，使用您的示例，您可以创建类似这样的内容

class Employee(models.Model):
    employee_id = models.ObjectIdField()
    employee_name = models.CharField(max_length=200, null=False, blank=False)
    email = models.EmailField(max_length=500, null=True, blank=True)

    def __str__(self):
        return self.employee_name

class PresentEmployee(models.Model):
    present_id = models.ObjectIdField()
    employee = models.EmbeddedField(model_container=Employee)
    id = models.UUIDField(default=uuid.uuid4, primary_key=True, editable=False)

    def __str__(self):
        return str(self.employee_id)