Post http Request Android studio 并获取变量中的json文件答案

【问题标题】：Post http Request Android studio and get the json file in variablesPost http Request Android studio 并获取变量中的json文件
【发布时间】：2022-08-09 18:59:50
【问题描述】：

将发布请求发送到 Spring Boot 数据库。

错误信息是 E/ERROR: java.io.IOException: 不允许到本地主机的明文 HTTP 流量

 RequestQueue queue = Volley.newRequestQueue(getApplicationContext());

                JSONObject newUserJsonObject = new JSONObject();

                try {
                    newUserJsonObject.put(\"email\", email.getText().toString());
                    newUserJsonObject.put(\"password\", password.getText().toString());
                    newUserJsonObject.put(\"kanton\", kanton.toString());
                    int intAge = Integer.parseInt(age.getText().toString());
                    newUserJsonObject.put(\"age\", intAge);
                } catch (JSONException e) {
                    Log.e(\"ERROR\", e.getMessage());
                }

                JsonObjectRequest jsonObjectRequest = new JsonObjectRequest(Request.Method.POST, url, newUserJsonObject, response -> openLoginActivity(), error -> Log.e(\"ERROR\", error.getMessage()));

                queue.add(jsonObjectRequest);
            }else
                //incorrect
                Toast.makeText(RegisterActivity.this, \"WRONG DATA\", Toast.LENGTH_SHORT).show();
        }
    });

    ActionBar actionBar = getSupportActionBar();
    if (actionBar != null) {
        getSupportActionBar().setDisplayHomeAsUpEnabled(true);
    }

    toLogin.setOnClickListener(v -> openLoginActivity());

和

此帖子已隐藏。您在 3 小时前删除了此帖子。我想在查询中获取属性的平均值，但只获取 Last 360 数据的平均值

我的查询是

@Query(nativeQuery = true, value = \"SELECT AVG(m.temperature), AVG(m.eCO2), AVG(m.humidity), AVG(m.pressure) FROM Measures as m join Devices d on devices_id = d.id where d.id = :devicesId order by m.id desc LIMIT 360\")

列出 findAverageFromTodayByUserId(@Param(\"devicesId\") int devicesId); 该代码在没有平均功能的情况下工作

@Query(value = \"SELECT * FROM Measures as m join Devices d on devices_id = d.id where d.id = :devicesId order by m.id desc LIMIT 360\", nativeQuery = true)

列出 findAllFromTodayByUserId(@Param(\"devicesId\") int devicesId);

    public static void main(String[] args) {
        int num2 = --num1;
        Test test = new Test();
        System.out.println(num2 + \"  \" + num1 + \"   \" + num1++ + \"   \" + num1 + \"   \" + (9 % 1));
        System.out.println(test instanceof Test);
        System.out.println(32 << 8); // left * binary digit of right + 1
        System.out.println(8192 >> 8); // left / binary digit of right + 1
        System.out.println(~9); // -1*value -1
        // -> filter and Runnable. lambda function
        Runnable r = () -> {
            System.out.println(\"Thread is running...\");
        };
        Thread t2 = new Thread(r);
        t2.start();
        System.out.println((byte) (Byte.MAX_VALUE + 1));

        String string = \"hello world bye moon\", stringTwo;
        String[] newStringArray;
        newStringArray = string.split(\" \");
        stringTwo = newStringArray[0] + \" \" + newStringArray[1];

        System.out.println(stringTwo);

        String string2 = \"hello world bye moon\";
        String firstTwo = string2.replaceAll(\"(\\\\w+ \\\\w+ \\\\w+).*\", \"$1\");
        System.out.println(firstTwo);  // hello world

        String string3 = \"hello world bye moon\";
        String stringTwo2 = string3.substring(0, string.indexOf(\' \', string.indexOf(\' \')+1));

        System.out.println(stringTwo2);

        String s = \"hello world people\";
        System.out.println(firstTwoWords(s, 3));
    }
}

感谢帮助

标签： android

【解决方案1】：

 static String firstTwoWords(String s, int amount){
        int spaces = 0;
        int i;
        for(i=0; i<s.length() && spaces < amount; i++)
            if (s.charAt(i) == ' ')
                spaces++;
        return s.substring(0, i);
    }

【讨论】：