【发布时间】：2022-08-04 15:33:23
【问题描述】：
所以，我在这里有一个 URL 列表，我想单独打印它们。
[\'https://gogoanime.gg/aware-meisaku-kun-episode-222\', \'https://gogoanime.gg/motto-majime-ni-fumajime-kaiketsu-zorori-3rd-season-episode-10\', \'https://gogoanime.gg/yugioh-go-rush-episode-18\', \'https://gogoanime.gg/tokyo-mew-mew-new-episode-5\', \'https://gogoanime.gg/jashin-chan-dropkick-x-episode-5\']
我想要这样的输出。怎么能得到这个
https://gogoanime.gg/aware-meisaku-kun-episode-222
https://gogoanime.gg/motto-majime-ni-fumajime-kaiketsu-zorori-3rd-season-episode-10
https://gogoanime.gg/yugioh-go-rush-episode-18
https://gogoanime.gg/tokyo-mew-mew-new-episode-5
https://gogoanime.gg/jashin-chan-dropkick-x-episode-5
这是代码
from operator import index
import re
from urllib import response
from venv import create
from bs4 import BeautifulSoup
from numpy import append
import numpy as np
import pandas as pd
import requests
import json
from gogo import links
iframe_url = links
New_links = (\',\'.join(links))
transformed_string=re.sub(\",\",\"\",new_links)
标签： python web web-scraping