扁平化仅包含一个 dict 的列表

Question

我有一个字典，其中包含一个列表product，它只包含一个字典：

d = {
    "thickness": 90.0,
    "mass_surf": 37.8,
    "res_therm": 0.75,
    "codename": "codename1",
    "category": "category1",
    "sub_categories": [
        "sub_categories1"
    ],
    "secondary_targets": [
        "secondary_targets1",
        "secondary_targets2",
        "secondary_targets3"
    ],
    "product": [
        {
            "codename": "codename1",
            "purpose": "purpose1",
            "category": "category1",
            "material": "material1"
        }
    ]
}

我想将 dict 的product 列表变平以获得这个：

d = {
    "thickness": 90.0,
    "mass_surf": 37.8,
    "res_therm": 0.75,
    "codename": "codename1",
    "category": "category1",
    "sub_categories": [
        "sub_categories1"
    ],
    "secondary_targets": [
        "secondary_targets1",
        "secondary_targets2",
        "secondary_targets3"
    ],
    "product.codename": "codename1",
    "product.purpose": "purpose 1",
    "product.purpose": "purpose1",
    "product.category": "category1",
    "product.material": "material1"
}

我该怎么做？

product 列表将始终只包含一项

Answer 1

您可以展平内部字典并将其更新回原始字典。 例如，

product = d.pop("product")[0]
flattened = {f"product.{key}": value for key, value in product.items()}
d.update(flattened)

这应该可以解决问题。