expo sendPushNotificationsAsync 静默失败答案

【问题标题】：expo sendPushNotificationsAsync fails silentlyexpo sendPushNotificationsAsync 静默失败
【发布时间】：2022-07-26 04:10:58
【问题描述】：

在调用sendPushNotificationsAsync 之后，我希望票会被退回。相反，我没有收到任何退票。

调用以下函数：（注意 console.log(ticketChunk); 不返回任何内容）。为什么我在此函数中没有收到任何票证并且没有触发任何错误？

const sendNotitifications = (messages) => {
    let chunks = expo.chunkPushNotifications(messages);
    let tickets = [];

    console.log("chunks: ",chunks);

    (async () => {
        for (let chunk of chunks) {
            try {
                let ticketChunk = await expo.sendPushNotificationsAsync(chunk);
                console.log(ticketChunk);  // <-- returns nothing
                tickets.push(...ticketChunk);
            } catch (err) {
                console.log(err);
            }
        }
    })();

    console.log("tickets: ",tickets);

    let stackTickets = [];
    for (let [i, ticketChunk] of tickets.entries()) {
        let chunk = chunks[i]
        ticketChunk.forEach((ticket, i) => {
            stackTickets.push({
                stack: chunk[i].data[StackID],
                ticket: ticket
            });
        });
    };

    console.log("stackTickets: ",stackTickets);

    return stackTickets;
};

产生以下结果：

chunks:  [
  [
    {
      to: 'ExponentPushToken[XXXXXXXXXXXXXXXXXXX]',
      sound: 'default',
      body: 'Time for Cheese!',
      data: [Object]
    },
    {
      to: 'ExponentPushToken[XXXXXXXXXXXXXXXXXXX]',
      sound: 'default',
      body: 'Time for Stackeroni!',
      data: [Object]
    }
  ]
]
tickets:  []
stackTickets:  []

【问题讨论】：

标签： javascript push-notification expo

【解决方案1】：

虽然听起来很奇怪，但请删除包装 for 循环的匿名函数。

这样做：

    for (let chunk of chunks) {
        try {
            let ticketChunk = await expo.sendPushNotificationsAsync(chunk);
            console.log(ticketChunk);
            tickets.push(...ticketChunk);
        } catch (err) {
            console.log(err);
        }
    }

代替：

(async () => {
    for (let chunk of chunks) {
        try {
            let ticketChunk = await expo.sendPushNotificationsAsync(chunk);
            console.log(ticketChunk);  // <-- returns nothing
            tickets.push(...ticketChunk);
        } catch (err) {
            console.log(err);
        }
    }
})();

这应该像一个魅力！

【讨论】：