【发布时间】:2022-07-22 02:47:55
【问题描述】:
导出的文件只包含一个 url。在导出的文件中找不到其余的 url。如何生成包含循环中所有条目的文件?
const puppeteer = require("puppeteer");
const fs = require('fs');
let browser;
(async () => {
const browser = await puppeteer.launch({
headless: true,
args: ['--no-sandbox']
});
const [page] = await browser.pages();
await page.goto('https://old.reddit.com/',{"waitUntil" : "networkidle0"});
const a_elems = await page.$$('.thumbnail');
for (var i=0; i<a_elems.length && i<3; i++) {
const elem = a_elems[i];
const href = await page.evaluate(e => e.href, elem);
const newPage = await browser.newPage();
await newPage.goto(href,{"waitUntil" : "networkidle0"});
const url = await newPage.evaluate(() => document.location.href);
console.log(url);
fs.writeFileSync('export.json', JSON.stringify(url));
}
await browser.close();
})()
;
谢谢!
【问题讨论】:
标签: javascript node.js json web-scraping puppeteer